Java：除最后一部分外，获取整个URL的最简单方法是什么？

Question

consider the url is

http://www.google.com/a/b/myendpoint

All I want is the following

http://www.google.com/a/b/

One approach is to split the String url and join all the components except last one.

I am thinking if there could be a better way?

Answer 1

You can use lastIndexOf() :

url.substring(0, url.lastIndexOf('/') + 1)

---

String url = "http://www.google.com/a/b/myendpoint";
System.out.println(url.substring(0, url.lastIndexOf('/') + 1));

http://www.google.com/a/b/

Answer 2

Use either of the following both are same

pathofURL = url.subString(0, url.lastIndexOf('/') + 1);

or if it has no Query

pathofURL = url.getProtocol() + "://" + url.getAuthority() + url.getPath();
pathofURL = pathofURL.subString(0, pathofURL.lastIndexOf('/') + 1);

It has Query alone

pathofURL = url.getProtocol() + "://" + url.getAuthority() + url.getPath();

It has Query and Reference

pathofURL = url.getProtocol() + "://" + url.getAuthority() + url.getFile();

Hope it helps, check the URL and use either of the above.

Answer 3

The simplest uses the URI.resolve method: url.toURI().resolve("").toURL() . (You could start immediately with URIs.)

URL url = new URL("http://www.google/intl/eo/index.html");
URL url2 = url.toURI().resolve("favicon.ico").toURL(); // Or "" for the question.
System.out.println("url2: " + url2.toExternalForm());

// url2: http://www.google/intl/eo/favicon.ico