[英]Regex for Alphanumeric, spaces and symbols, Doesn't match like i need
I want to make a regular expression that matches : 我想制作一个匹配的正则表达式:
-alphanumeric with spaces -these symbols and letters - 带空格的字母数字 - 这些符号和字母
á é í ó ú ñ Ñ ,.( ) ! - + % $
I tried with this, but it didn't match like i need: 我试过这个,但它不符合我的需要:
[\w áéíóúñÑ,.\(\)\!\-\+\%\$]
What's wrong in this regex?? 这个正则表达式有什么问题?
I'm using knockoutjs with knockout validation 我正在使用敲除验证的knockoutjs
.extend({pattern:{message:"No valid.",params:"[\w áéíóúñÑ,.\(\)\!\-\+\%\$]"}});
tested on chrome, firefox, IE10 and Safari browser. 在chrome,firefox,IE10和Safari浏览器上测试过。
You need to escape the special \\
escape character to place an actual \\
in the string. 您需要转义特殊的
\\
escape字符以在字符串中放置一个实际的\\
。 Also, you do not need to escape all these characters, just the ones that have a special meaning within the brackets. 此外,您不需要转义所有这些字符,只需要在括号内具有特殊含义的字符。
Try with: 试试:
"[\\w áéíóúñÑ,.()!\\-+%$]"
this pass ----> "||°°dafsasdf" but this didnt pass the valid ---> "||°°"
这个传球---->“||°°dafsasdf”但这没有通过有效的--->“||°°”
Oh, it's because right now as long as a single character in the string matches the regex, it will pass. 哦,这是因为现在只要字符串中的单个字符与正则表达式匹配,它就会通过。 You have to create a whole pattern match with a defined start and end .
您必须使用定义的开始和结束创建整个模式匹配。
"^[\\w áéíóúñÑ,.()!\\-+%$]*$"
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