[英]why is resultset.next() returning null
in the code below the method resultset.next() is returning false 在方法resultet.next()下面的代码中返回false
String sql = "{?= call fun_consolidate_retrieve_vector_receipt_payment_details(?,?,?,?,?,?)}";
callableStatement = con.prepareCall(sql);
callableStatement = con.prepareCall(" {? = call fun_retrieve_vector_receipt_payment_details(?,?,?,?,?,?)}");
callableStatement.registerOutParameter(1, Types.OTHER);
callableStatement.setString(2, "PAYMENT");
callableStatement.setInt(3, 47);
callableStatement.setString(4, "24-05-2013");
callableStatement.setString(5, "24-09-2013");
callableStatement.setString(6, "Y");
callableStatement.setObject(7, resultSet);
con.setAutoCommit(false);
callableStatement.execute();
resultSet = (ResultSet) callableStatement.getObject(1);
boolean next = resultSet.next();
Why is it so??? 为什么会这样??? if i call same stored procedure from my database it results in 2 rows of output(provding same input as in java code) 如果我从数据库中调用相同的存储过程,则会导致两行输出(提供与Java代码相同的输入)
Your title expresses your confusion. 您的头衔表达了您的困惑。 ResultSet.next() returns a boolean, not anything that can be null. ResultSet.next()返回一个布尔值,而不是任何可以为null的值。 You need to call it before getObject(), not afterwards. 您需要在 getObject() 之前调用它,而不是在之后调用它。
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