[英]Load java.io.File At Runtime On Classpath
I have two jars (main.jar and schema.jar) and I need to read a schema file (located in src/main/resources/sample.xsd) from schema.jar in a class within main.jar. 我有两个jar(main.jar和schema.jar),我需要从main.jar中的类中的schema.jar读取模式文件(位于src / main / resources / sample.xsd中)。 main.jar has schema.jar on its classpath as a maven dependency.
main.jar在其类路径上具有schema.jar作为Maven依赖项。 I'm able to find the sample.xsd file when I use the this.getClass().getClassLoader().getResourceAsStream, but I need a java.io.File.
使用this.getClass()。getClassLoader()。getResourceAsStream时,我可以找到sample.xsd文件,但我需要一个java.io.File。 What is the most memory efficient approach to supply the java.io.File parameter?
提供java.io.File参数最节省内存的方法是什么?
main.jar: main.jar:
InputStream in = this.getClass().getClassLoader()
.getResourceAsStream("/resources/sample.xsd");
Sample sample = new Sample();
//set sample data here
Marshaller marshaller = JAXBContext.newInstance(Sample.getClass()).createMarshaller();
final SchemaFactory schemaFactory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
final Schema s = schemaFactory.newSchema(new File("/resources/sample.xsd"));
marshaller.setSchema(s);
marshaller.marshal(Sample, XML);
Just use SchemaFactory#newSchema(URL)
method instead. 只需使用
SchemaFactory#newSchema(URL)
方法即可。
URL url = getClass().getClassLoader().getResource("/resources/sample.xsd");
// ...
final Schema s = schemaFactory.newSchema(url);
No need to massage the InputStream
into a File
which isn't nicely possible anyway (you could create a temp file, but that's plain clumsy). 无需将
InputStream
压缩到一个File
,这是不可能的(您可以创建一个临时文件,但这很笨拙)。 JAXB will under the covers grab the InputStream
from the supplied URL
by URL#openStream()
. JAXB会在
URL#openStream()
通过URL#openStream()
从提供的URL
获取InputStream
。
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