将 python 脚本作为 Windows 服务运行

Question

Is there a way to run my python 3 script at system boot on windows 7?

I know this has been asked a couple of times, but none of the solutions really filled my needs, because I prefer to stay with the free python interpreter rather than switching to ActivePython.

I have installed the Python for Windows extensions and would use py2exe, but it does not support Python 3.

Answer 1

You can also use the Windows Task Scheduler using the following steps (skip quotes when typing):

• Search 'Task Scheduler' in Start button search box
• Create a new task
• In 'Create Task' dialog, go to 'Triggers' tab and click 'New' button
• Select 'At startup' from the 'Begin the task' dropdown, click 'OK'
• Go to 'Actions' tab and click 'New' button
• 'Action' dropdown should show 'Start a program'
• In 'Program/script' box, type 'python.exe'
• In 'Add arguments' box, type the full path to your python script with any arguments, such as 'C:\\Scripts\\startupscript.py -c onstart'

Answer 2

Assuming that you have a fully woking stand alone exe file that's been generated from your python script using py2exe , you can just add a new string with some random key and value as the absolute path of your exe file under HKLM\\Software\\Microsoft\\Windows\\CurrentVersion\\Run of windows registry (accessible by running regedit from Window's run prompt). This will run the exe file whenever your Windows 7 boots up !

Answer 3

You can use the sc command. I am unable to test it right now but i think it would look like this:

sc create MyCoolService start=auto binpath=c:\mycoolprogram\supercool.exe obj=LocalSystem displayname=CoolService

See link for command syntax