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使用gson解析具有相同名称的json变量对象

[英]Parsing json variable objects with same name using gson

Hi I want to parse the json 嗨,我想解析json

 {
        "entityType":"Account",


        "values":[
                {
                    "name":"accountType",
                    "type":"lookup",
                    "typeinfo":{"entity":"lov", "filter":"LOV_ACCOUNT_TYPE"}
                },
                {
                    "name":"irstSubType",
                    "type":"lookup",
                    "typeinfo":{"entity":"lov", "filter":"LOV_ACCOUNT_TYPE"}
                },
                {
                    "name":"accountStatus",
                    "type":"lookup",
                    "typeinfo":{"entity":"lov", "filter":"LOV_ACCOUNT_STATUS"}
                },
                {
                    "name":"name",
                    "type":"string",
                    "typeinfo":{"width":80}
                },
                {
                    "name":"updated",
                    "type":"datetime",
                    "typeinfo":{"format":"dd/MM/yyyy hh:MM:ss"}
                }
          ]
    }

So here typeinfo object implementation is changing.. any suggessions how does Gson library accomodate this? 所以这里的typeinfo对象实现正在改变..任何建议Gson库如何适应这一点? Interface does not work. 界面不起作用。

Value

public class Value {
private String name;
private String type;    
private  TypeInfo typeinfo;
public String getName() {
    return name;
}
public String getType() {
    return type;
}
public TypeInfo getTypeinfo() {
    return typeinfo;
}
}

MyGson 麦格森

public class MyGson {
private String entityType;
private List<Value> values;

public String getEntityType() {
    return entityType;
}
public List<Value> getValues() {
    return values;
}
}

TypeInfo 类型信息

public class TypeInfo {

private String format;
private String entry;
private String filter;

public String getFormat() {
    return format;
}

public String getEntry() {
    return entry;
}

public String getFilter() {
    return filter;
}
}

Launcher 发射器

    Gson gson = new Gson();

    MyGson myGson = gson.fromJson(str, MyGson.class);

    List<Value> values = myGson.getValues();


    for(Value value : values){

        str = value.getTypeinfo().getFormat();


        printValues("format", value.getTypeinfo().getFormat());
        printValues("entry", value.getTypeinfo().getEntry());
        printValues("filter", value.getTypeinfo().getFilter());
        //....
    }




}

private static void printValues(String key, String data){
    if(data != null){
        System.out.println(key + ": " + data);
    }
}

Output: 输出:

filter: LOV_ACCOUNT_TYPE
filter: LOV_ACCOUNT_TYPE
filter: LOV_ACCOUNT_STATUS
format: dd/MM/yyyy hh:MM:ss

Despite the other answers, it is not a good idea to have a field for each of the possible variables in typeinfo, as two fields could have same name but different types. 尽管有其他答案,但在typeinfo中为每个可能的变量都具有一个字段并不是一个好主意,因为两个字段可能具有相同的名称但类型不同。

What you really want to do, is to turn the data from typeinfo into a Map<String, Object>. 您真正想要做的是将数据从typeinfo转换为Map <String,Object>。

This is difficult in Gson, but it is possible using a deserializer - see Kevin's answer for an example of this: https://stackoverflow.com/a/4799594/1660737 这在Gson中很难,但是可以使用解串器-有关示例,请参见Kevin的答案: https : //stackoverflow.com/a/4799594/1660737

        String s = "...json string ..";
        JSONParser jsonparser = new JSONParser();
        JSONObject jsonObject = (JSONObject)jsonparser.parse(s);
        JSONArray values = (JSONArray) jsonObject.get("values");

        for(int i=0; i< values.size(); i++){
            JSONObject value = (JSONObject)values.get(i);
            JSONObject typeInfo = (JSONObject)value.get("typeinfo");
            Iterator it = typeInfo.keySet().iterator();
            while(it.hasNext()){
                Object key = it.next();
                System.out.println("KEY:" + key + " VALUE:" + typeInfo.get(key));
            }
        }

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