获取父文件的文件夹名称

Question

I'm working with some code and I want it to behave differently depending on the folder name that the file is in. I don't need the absolute path just the final folder. Everything that I have seen so far is using a absolute path that is specified in the file.

Answer 1

This is what you want:

public static String getParentName(File file) {
    if(file == null || file.isDirectory()) {
            return null;
    }
    String parent = file.getParent();
    parent = parent.substring(parent.lastIndexOf("\\") + 1, parent.length());
    return parent;      
}

Unfortunately there is no pre-provided method that just returns the name of the last folder in the file's path, so you have to do some String manipulation to get it.

Answer 2

Try java.io.File.getParentFile() method.

String getFileParentName(File file) {
    if (file != null && file.getParentFile() != null) {
        return file.getParentFile().getName();
    }
    return null; // no parent for file
}

Answer 3

I think java.io.File.getParent() is what you are looking for:

import java.io.File;

public class Demo {

   public static void main(String[] args) {
      File f = null;
      String parent="not found";
      f = new File("/tmp/test.txt");
      parent = f.getParent();
      System.out.print("parent name: "+v);
   }

}

Answer 4

There's

String File.getParent()

There's also

File File.getParentFile()

I don't know what the return in terms of being absolute or relative, but if it's absolute you can always find the last (or second to last, depending) instance of the "\\" character (remember to escape it like this "\\\\") to denote where the lowest folder level is.

For example, if the function returned:

"C:\\Users\\YourName" is where you'd get the last occurance of "\\", and all characters after it would be the folder you want

"C:\\Users\\YourName\\" is where you'd get the second to last occurance of "\\", and all characters between that and the last "\\" would be the folder you're looking for.

Java File API: http://docs.oracle.com/javase/7/docs/api/java/io/File.html

Answer 5

String path = "/abc/def"; // path to the directory  
try
{
    File folder = new File(path);
    File[] listOfFiles = folder.listFiles();

    for (File file : listOfFiles) 
    {
      if(file.isDirectory())
      {
        switch(file.getName)
        {
             case "folder1" : //do something
              break
             case "folder2" : //do something else 
              break
        }  
      }
    }
}   
catch(Exception e) 
{
      System.out.println("Directory not Found"); 
}