[英]Reading data from text file in Java
i have a text file with contents: 我有一个包含内容的文本文件:
26/09/2013,16:04:40 2412 -928.0
25/09/2013,14:24:30 2412 914.0
The file above contains a date, time an integer and a double on each line 上面的文件在每个行上包含日期,时间,整数和双精度
I have made a class to contain the data once it is read in: 一旦读入数据,我就创建了一个包含数据的类:
public class Entry{
public String date, time;
public int integerNumber;
public double doubleNumber;
public Entry(String d, String t, int n1, double n2){
this.date=d;
this.time=t;
this.integerNumber=n1;
this.doubleNumber=n2;
}
}
What is the best way to read the above file into an Entry[] array where each element in the array is the data from each line? 将上述文件读入Entry []数组的最佳方法是什么,该数组中的每个元素都是每一行的数据?
EDIT : My current attempt involves reading each line as a String and creating substrings for the various pieces of data eg String date=line.substring(0,10);
编辑 :我目前的尝试涉及将每一行作为一个字符串读取,并为各种数据创建子字符串,例如String date=line.substring(0,10);
This works fine for now but when i get to the integer for example, it wont necessarily be a 4 digit number. 这现在可以正常工作,但是例如当我到达整数时,它不一定是4位数字。 This leaves me stuck as i don't know how to read a number of arbitrary size. 这使我陷入困境,因为我不知道如何读取任意大小的数字。
You can use a regular expression to read the text file. 您可以使用正则表达式来读取文本文件。
For example, 例如,
String line = "001 John Smith";
String regex = "(\\d)+ (\\w)+ (\\w)+";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(line);
while(matcher.find()){
String [] group = matcher.group().split("\\s");
System.out.println("First Name "+group[1]);
System.out.println("Last Name " +group[2]);
}
Well, if you can guarantee that all your lines in the file you're reading have the following format 好吧,如果可以保证正在读取的文件中的所有行都具有以下格式
<date>,<time> <integer> <double>
You could read it like this 你可以这样看
String foo = "25/09/2013,14:24:30 2412 914.0";
String delims = "[, ]+";
String[] tokens = foo.split(delims);
String d = tokens[0]; // d would contain the string '25/09/2013'
String t = tokens[1]; // t would contain the string '14:24:30'
int n1 = Integer.parseInt(tokens[2]); // n1 would contain the integer 2412
double n2 = Double.parseDouble(tokens[3]); // n2 would contain the double 914.0
You can use Scanner for this. 您可以为此使用扫描仪 。
It has constructor which takes File
and also has next()
, nextInt()
, nextDouble()
methods to read String,int,double
respectively. 它具有构造函数,该构造函数采用File
,还具有next()
, nextInt()
和nextDouble()
方法分别读取String,int,double
。
For sample code reference link : http://www.cs.utexas.edu/users/ndale/Scanner.html 有关示例代码参考链接: http : //www.cs.utexas.edu/users/ndale/Scanner.html
Could be done by using Use Apache Commons FileUtils 可以通过使用Use Apache Commons FileUtils完成
File file = new File("/yourfile.txt");
List<String> lines = FileUtils.readLines(file, null);
List<Entry> entries = new ArrayList<Entry>();
for (String line : lines) {
//line == 26/09/2013,16:04:40 2412 -928.0
Entry entry = createEntry(line); // parse string and create a Entry...
entries.add(entry);
}
// Warning, not safe and not pretty...
private static Entry createEntry(String line) {
String[] parts = line.split(" ");
String[] datePart = parts[0].split(",");
return new Entry(datePart[0],
datePart[1],
Integer.valueOf(parts[1]),
Double.valueOf(parts[2])
);
}
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