从ajax php调用创建2D javascript数组

Question

I have a mysql table with image data in.

I want to retrieve the image data and push into a javascript array.

There are two fields that I want to put into the array and they are image_ref, and image_name I know I need a 2D array for this and I need to retrive the data from the db using ajax and JSON.

I am not sure how to complete this.

I know I need to call the php page with a JSON ajax call

js:

var imagesArray[];

$.getJSON("get_image_data.php")
    .done(function(data) { 
  /*THIS IS WHERE I NEED HELP---*/
});         

get_image_data.php page

include("connect.php"); 
$query = mysql_query("SELECT * FROM images WHERE live='1' ORDER BY insertDate DESC");
while($row=mysql_fetch_array($query){
     echo json_encode(array("a" => $row['image_ref'], "b" => $row['image_name'])); 
}

I have highlighted where I need help in getting the returned data into the stockImages array.

Can anyone show me the light?

thanks in advance

Answer 1

By calling json_encode() multiple times in your loop, you are creating lots of singular bits of JSON. You should aim at creating and transmitting one transfer object, like this:

include("connect.php"); 
$query = mysql_query("SELECT * FROM images WHERE live='1' ORDER BY insertDate DESC");
$images = array(); 
while($row=mysql_fetch_array($query){
    $images[] = array("a" => $row['image_ref'], "b" => $row['image_name']); 
}
echo json_encode($images);

This will give you one JSON array, through which you can loop in your client side Javascript.

Answer 2

Actually, it is PHP that is wrong, 'cause on JS you will have the array you need directly in "data".

You PHP code should look like:

$query = mysql_query("SELECT * FROM images WHERE live='1' ORDER BY insertDate DESC");
$result = array();
while($row=mysql_fetch_array($query){
    $result[] = array("a" => $row['image_ref'], "b" => $row['image_name']); 
}
echo(json_encode($result));