[英]Hibernate - createNativeQuery with “non-entity class” result
I'm new to all this Hibernate/JPA stuff, so i will try to be as clear as possible. 我是所有这些Hibernate / JPA的新手,所以我会尽量清楚。
Is there any way in Hibernate to use createNativeQuery to select a single/or multiple fields in a query without using an Entity class as the return object ? 在Hibernate中有没有办法使用createNativeQuery在查询中选择单个/或多个字段而不使用Entity类作为返回对象?
I'm trying to do this without using any XML related stuff. 我试图这样做而不使用任何与XML相关的东西。
Query query = getEntityManager().createNativeQuery("select name from contact where id_contact = :idContact", String.class);
query.setParameter("idContact", 9293L);
Object string = query.getSingleResult();
System.out.println(string);
Using this i have the Exception : Exception in thread "main" javax.persistence.PersistenceException: org.hibernate.MappingException: Unknown entity: java.lang.String
使用这个我有异常:
Exception in thread "main" javax.persistence.PersistenceException: org.hibernate.MappingException: Unknown entity: java.lang.String
Thanks 谢谢
Edit : 编辑:
I also tried : 我也尝试过:
Query query = getEntityManager().createNativeQuery("select name from contact where id_contact = :idContact");
query.setParameter("idContact", 9293L);
List list = query.getResultList();
if (!list.isEmpty()){
Object string = list.get(0);
System.out.println(string);
}
With the same Exception : Exception in thread "main" java.lang.ClassCastException: java.lang.String cannot be cast to [Ljava.lang.Object;
使用相同的异常:
Exception in thread "main" java.lang.ClassCastException: java.lang.String cannot be cast to [Ljava.lang.Object;
Edit (2) : I'm starting to think it's either a bug in Hibernate or it's impossible to do such things... 编辑(2):我开始认为它是Hibernate中的一个错误,或者不可能做这样的事情......
The problem is that you are passing String.class
as the second parameter to createNativeQuery
. 问题是您将
String.class
作为createNativeQuery
的第二个参数createNativeQuery
。 This will make hibernate attempt to use the String.class
to create a mapping for the result set. 这将使hibernate尝试使用
String.class
为结果集创建映射。 It can only create this mapping from entity classes and String
is not an entity class because it isn't mapped to a table. 它只能从实体类创建此映射,而
String
不是实体类,因为它未映射到表。
Fortunately, the solution is to simply use an overloaded version of createNativeQuery
that doesn't require a second parameter. 幸运的是,解决方案是简单地使用不需要第二个参数的
createNativeQuery
的重载版本。
String SQL = ".."; //same SQL as you had before
Query query = getEntityManager().createNativeQuery(SQL); //no entity mapping
query.setParameter("idContact", 9293L);
Object string = query.getSingleResult();
System.out.println(string);
In case of Native query or jpql with column name EntityManager Returns a List of array of objects. 如果是Native查询或带有列名的jpql,则EntityManager返回一个对象数组的List。
so to get Result List. 所以要获得结果列表。
receive it in a 收到它
List<Object[]> listResults = query.getResultList();
then iterate over it:- 然后迭代它: -
for (Object[] record : listResults) {
//Iterate Logic will come here
}
Just try to call createNativeQuery()
without passing String.class
. 只是尝试调用
createNativeQuery()
而不传递String.class
。 If the name
column is of string-type in database query.getSingleResult()
will actually return a String
. 如果
name
列在数据库query.getSingleResult()
是string-type,则实际上将返回一个String
。
try 尝试
Query query = getEntityManager().createNativeQuery("select name from contact where id_contact = :idContact", String.class);
query.setParameter("idContact", 9293L);
List list = query.getResultList();
if (!list.isEmpty()){
Object string = list.get(0);
System.out.println(string);
}
In the Look here 在这里看
http://sysout.be/2011/03/09/why-you-should-never-use-getsingleresult-in-jpa http://sysout.be/2011/03/09/why-you-should-never-use-getsingleresult-in-jpa
String SQL = ".."; //same SQL as you had before
Query query = getEntityManager().createNativeQuery(SQL); //no entity mapping
query.setParameter("idContact", 9293L);
String string = (String)query.getSingleResult();
System.out.println(string);
For Hibernate 5.0 对于Hibernate 5.0
Query query = getEntityManager().createNativeQuery(sql);
List<Object[]> objects = query.getResultList();
System.out.println(objects.get(0)[0]);
https://docs.jboss.org/hibernate/orm/5.0/userguide/html_single/chapters/query/native/Native.html https://docs.jboss.org/hibernate/orm/5.0/userguide/html_single/chapters/query/native/Native.html
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