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最近5天的SAS返回数据

[英]SAS Return data from the last available 5 days

I have a list of intra-day prices at 9am, 10am, 11am etc. for each day (which are in number formats such as 15011 15012 etc.) 我有每天上午9点,上午10点,上午11点等的日内价格列表(格式为15011 15012等)。

I want to only keep the observations from the last available 5 days and the next 5 available days from the date 't' and delete everything else. 我只想保留从“ t”日期开始的最近5天和接下来的5天的观测值,并删除其他所有内容。 Is there a way to do this? 有没有办法做到这一点?

I tried using if date < &t - 5 or date > &t + 5 then delete; 我尝试使用日期<&t-5或日期>&t + 5然后删除; However, since there are weekends/holidays I don't get all the observations I want. 但是,由于有周末/节假日,所以我没有得到我想要的所有观察结果。

Thanks a lot in advance! 在此先多谢!

Not much info to go on, but here is a possible solution: 信息不多,但是下面是一个可能的解决方案:

/* Invent some data */
data have;
  do date=15001 to 15020;
     do time='09:00't,'10:00't,'11:00't;
        price = ranuni(0) * 10;
        output;
        end;
     end;
run;

/* Your macro variable identifying the target "date"  */
%let t=15011;

/* Subset for current and following datae*/
proc sort data=have out=temp(where=(date >= &t));
   by date;
run;

/* Process to keep only current and following five days */
data current_and_next5;
   set temp;
      by date;
   if first.date then keep_days + 1;  /* Set counter for each day */
   if keep_days <= 6;                 /* Days to keep (target and next five) */
   drop keep_days;                    /* Drop this utility variable */
run;

/* Subset for previous and sort by date descending */
proc sort data=have out=temp(where=(date < &t));
   by descending date;
run;

/* Process to keep only five previous days */
data prev5;
   set temp;
      by descending date;
   if first.date then keep_days + 1;  /* Set counter for each day */
   if keep_days <= 5;                 /* Number of days to keep */
   drop keep_days;                    /* Drop this utility variable */
run;

/* Concatenate together and re-sort by date */

data want;
   set current_and_next5
       prev5;
run;

proc sort data=want;
   by date;
run;

Of course, this solution suggests that your starting data contains observations for all valid "trading days" and returns everything without doing date arithmetic. 当然,此解决方案建议您的起始数据包含对所有有效“交易日”的观察值,并且不进行日期算术就返回所有内容。 A much better solution would require that you create a "trading calendar" dataset with all valid dates. 更好的解决方案将要求您创建一个包含所有有效日期的“交易日历”数据集。 You can easily deal with weekends, but holidays and other "non-trading days" are very site specific; 您可以轻松地度过周末,但是假期和其他“非交易日”是特定于站点的。 hence using a calendar is almost always preferred. 因此,几乎总是首选使用日历。

UPDATE: Joe's comment made me re-read the question more carefully. 更新:乔的评论使我更仔细地重新阅读了问题。 This should return a total of eleven (11) days of data; 这应该返回总共十一(11)天的数据; five days prior, five days following, and the target date. 前五天,后五天和目标日期。 But still, a better solution would use a calendar reference table. 但是,更好的解决方案是使用日历参考表。

Try this 尝试这个

/* Get distinct dates before and after &T */
proc freq data=mydata noprint ;
  table Date /out=before (where=(Date < &T)) ;
  table Date /out=after (where=(Date > &T)) ;
run ;

/* Take 5 days before and after */
proc sql outobs=5 ;
  create table before2 as
  select Date 
  from before 
  order by Date descending ;

  create table after2 as
  select Date 
  from after 
  order by Date ;
quit ;

/* Subset to 5 available days before & after */
proc sql ;
  create table final as
  select *
  from mydata 
  where Date >= (select min(date) from before2)
    and Date <= (select max(date) from after2)
  order by Date ;
quit ;

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