RxJava线程安全

Question

Is this code thread-safe?

Observable<String> observable = ... // some observable that calls
                                    // onNext from a background thread

observable
  .scan(new ArrayList<String>(), (List<String> acc, String next) -> {
    acc.add(next);
    return acc;
  })
  .subscribe( list -> {
    // do somethind with sequence of lists
    ...
  });

I'm curious because ArrayList is not a thread-safe data structure.

Answer 1

As a quick answer, in .NET (the original Rx implementation) all values from an observable sequence can be assumed to be sequential. This does not preclude it to be multi-threaded. However if you are producing values in a multi-threaded manner, then you may want enforce the sequential nature by looking for the equivalent function to the .NET Synchronize() Rx operator.

Another option is to check the implementation of Scan in the RxJava source code, to validate that it does enforce the sequential nature you would want/expect to provide you safety in your accumulator function.

Answer 2

如果此代码不是线程安全的，则RxJava被破坏或您的Observable源被破坏 - 不可重入的运算符是Rx契约的一部分。