正则表达式从字符串中删除圆括号

Question

i have a string

String s="[[Identity (philosophy)|unique identity]]";

i need to parse it to .

s1 = Identity_philosphy 
s2= unique identity

I have tried following code

Pattern p = Pattern.compile("(\\[\\[)(\\w*?\\s\\(\\w*?\\))(\\s*[|])\\w*(\\]\\])");
  Matcher m = p.matcher(s);
while(m.find())
{
....
}

But the pattern is not matching..

Please Help

Thanks

Answer 1

Use

String s="[[Identity (philosophy)|unique identity]]";
String[] results = s.replaceAll("^\\Q[[\\E|]]$", "")    // Delete double brackets at start/end
      .replaceAll("\\s+\\(([^()]*)\\)","_$1")           // Replace spaces and parens with _
       .split("\\Q|\\E");                               // Split with pipe
System.out.println(results[0]);
System.out.println(results[1]);

Output:

Identity_philosophy
unique identity

Answer 2

Have you tried using something like this to help you? RegExr

Using that website I was able to create a pattern which will match exactly what you want.

This will work on that website: (\\[\\[)|(\\()|(\\))|(\\|)|(\\]\\])

Insert double backslashes for it to work within Java: (\\\\[\\\\[)|(\\\\()|(\\\\))|(\\\\|)|(\\\\]\\\\])

Answer 3

You may use

String s="[[Identity (philosophy)|unique identity]]";
Matcher m = Pattern.compile("\\[{2}(.*)\\|(.*)]]").matcher(s);
if (m.matches()) {
    System.out.println(m.group(1).replaceAll("\\W+", " ").trim().replace(" ", "_")); // // => Identity_philosphy
    System.out.println(m.group(2).trim()); // => unique identity
}

See a Java demo .

Details

The "\\\\[{2}(.*)\\\\|(.*)]]" with matches() is parsed as a ^\\[{2}(.*)\\|(.*)]]\\z pattern that matches a string that starts with [[ , then matches and captures any 0 or more chars other than line break chars as many as possible into Group 1, then matches a | , then matches and capture any 0 or more chars other than line break chars as many as possible into Group 2 and then matches ]] . See the regex demo .

The contents in Group 2 can be trimmed from whitespace and used as is, but Group 1 should be preprocessed by replacing all 1+ non-word character chhunks with a space ( .replaceAll("\\\\W+", " ") ), then trimming the result ( .trim() ) and replacing all spaces with _ ( .replace(" ", "_") ) as the final touch.