[英]math.random, only generating a 0?
The following code is only producing a 0 ;-;以下代码仅产生 0 ;-;
What am I doing wrong?我究竟做错了什么?
public class RockPaperSci {
public static void main(String[] args) {
//Rock 1
//Paper 2
//Scissors 3
int croll =1+(int)Math.random()*3-1;
System.out.println(croll);
}
}
Edit, Another Poster suggested something that fixed it.编辑,另一张海报建议了一些修复它的东西。 int croll = 1 + (int) (Math.random() * 4 - 1);
int croll = 1 + (int) (Math.random() * 4 - 1);
Thanks, everyone!谢谢大家!
You are using Math.random()
which states您正在使用
Math.random()
,其中说明
Returns a
double
value with a positive sign, greater than or equal to0.0
and less than1.0
.返回一个带正号的
double
精度值,大于或等于0.0
且小于1.0
。
You are casting the result to an int
, which returns the integer part of the value, thus 0
.您将结果转换为
int
,它返回值的整数部分,因此为0
。
Then 1 + 0 - 1 = 0
.然后
1 + 0 - 1 = 0
。
Consider using java.util.Random
考虑使用
java.util.Random
Random rand = new Random();
System.out.println(rand.nextInt(3) + 1);
Math.random()
generates double values between range - [0.0, 1.0)
. Math.random()
在范围 - [0.0, 1.0)
之间生成双精度值。 And then you have typecasted the result to an int
:然后您将结果类型转换为
int
:
(int)Math.random() // this will always be `0`
And then multiply by 3
is 0
.然后乘以
3
是0
。 So, your expression is really:所以,你的表达真的是:
1 + 0 - 1
I guess you want to put parenthesis like this:我猜你想像这样放置括号:
1 + (int)(Math.random() * 3)
Having said that, you should really use Random#nextInt(int)
method if you want to generate integer values in some range.话虽如此,如果你想在某个范围内生成整数值,你真的应该使用
Random#nextInt(int)
方法。 It is more efficient than using Math#random()
.它比使用
Math#random()
更有效。
You can use it like this:你可以这样使用它:
Random rand = new Random();
int croll = 1 + rand.nextInt(3);
See also:也可以看看:
One of the easiest ways to randomly generate 0 or 1 in Java: 在Java中随机生成0或1的最简单方法之一:
(int) (Math.random()+0.5);
or
(int) (Math.random()*2);
public static double random()
Returns a double value with a positive sign, greater than or equal to 0.0 and less than 1.0.返回带正号的双精度值,大于或等于 0.0 且小于 1.0。 Returned values are chosen pseudorandomly with (approximately) uniform distribution from that range.
返回值是伪随机选择的,具有该范围内的(近似)均匀分布。
int croll =1+(int)Math.random()*3-1;
eg例如
int croll =1+0*-1;
System.out.println(croll); // will print always 0
All our mates explained you reasons of unexpected output you got.我们所有的伙伴都向您解释了意外输出的原因。
Assuming you want generate a random croll
假设你想生成一个随机
croll
Consider Random
for resolution考虑
Random
的分辨率
Random rand= new Random();
double croll = 1 + rand.nextInt() * 3 - 1;
System.out.println(croll);
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