包含对象属性和打印/返回对象Python的搜索列表

Question

I've got a object in which I'm searching if the attribute title matches with my search

class Something(object):
    def __init__(self,title):
        self.title = title

    def __str__(self):
        return "%s is the title " % self.title

How can I print the object when it's invoked? Here is how I'm searching for it.

search = " ".join(s[1:]).lower()
if any(search in str(a.title).lower() for a in something):
    print filter(lambda x: search in str(x.title),something)

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If any(...) will check if any part of the search matches with my object's title and will return true if found anything.

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filter(...) prints the object, but here is where I'm having issues with it prints:

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[<__main__.Something object at 0x0000000002C93B38>, <__main__.Something object at 0x0000000002D33828>]

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I know that this is an object, why is it not printing through the __str__(self) method? How can I evoke the print function from my object Something ?

Answer 1

Generally, I would create a filter first to get the items which match your criteria. Then I would iterate over that and do whatever you want with it:

generator = (x for x in something if search in str(x.title).lower())
for item in generator:
   print item

The advantage here is that you do the filtering ahead of time (without filter ) and you only do the filtering test once.

Answer 2

You're printing the string representation of the list , and not each item in the list.

You can do:

print map(str, filter(lambda x: search in str(x.title),something))