正则表达式替换[*

Question

How to replace the string using regular expression for the following pattern

[*1. Introduction*]

to

1. Introduction

i've replaced it simply by

string s="[*1. Introduction*]";
s.Replace("[*", string.Empty).Replace("*]", string.Empty);

is it any equivalent for this using regular expression in c#.

Answer 1

Yes..

 Regex.Replace(s,"^\\[\\*|\\*\\]$", string.Empty);

Though I recommend you to stick with String's Replace method..

Answer 2

The advantage of using a regular expression for this, would be to assure that it wouldn't replace any [* or *] that would occur by themselves. The pattern can match the occurance of both.

A limitation of using such a pattern would be that it can't handle nested occurances, eg "Some [*text [*with*] nested*] tags." .

Performance for using a regular expression compared to String.Replace would be about the same. There is some overhead when creating the regular expression, but you need to run through the string twice when you use String.Replace .

Using a regular expression would look like this:

s = Regex.Replace(s, @"\[\*(.+)\*\]", "$1");

The parentheses in the pattern captures what's within the tags, and $1 in the replacement string uses what was captured to replace the entire tag.

Answer 3

就像@BenRobinson所说的，顺便说一句，我不知道这件事：D

string s = " [*1. Introduction*] ".Trim(' ', '[', ']', '*');