Javascript正则表达式匹配除了双空格然后替换的所有内容

Question

I need a regex that will match anything except white spaces or only words in between double spaces.

Like :

let's assume the underscores where equal to spaces just for example.

foo_bar__The_Quick_Dog__is_addicted_to___jumping___

Then replace the spaces with any symbol , preferably a Comma (,) .

So we should have: foo bar, The Quick Dog, is addicted to, jumping.

However, the word jumping should NOT have it's white spaces replaced with comma because it's at the end... adding a comma to it will be meaningless

I tried:

/\(\s*([^)]+?)\s*\)/

and

[a-z].\s{2,}.*

and

\s\s.*[a-z]

and

(?:[a-zA-Z0-9]+[ ])+[a-zA-Z0-9]+

and a few hundreds more... still no good.

Thank

Answer 1

So you mean like this?

var str = 'foo bar  The Quick Dog  is addicted to  jumping   ';
str.replace(/\s\s+/g, ', ').replace(/, (\n|$)/g, '.$1');
"foo bar, The Quick Dog, is addicted to, jumping."

Replace multi-spaces with "comma space" , then replace "comma space new line" or "comma space end" with "full stop new line" or "full stop end" , respectively.

Answer 2

Using a replacer ( mdn doc ) :

var s = 'foo bar  The Quick Dog  is addicted to jumping  ';
s.replace(/ {2,}(.)?/g, function (m, p) { return p ? ', ' + p : '.'; });
// prints "foo bar, The Quick Dog, is addicted to jumping."

Using match + join . This one also trims out the leading whitespaces :

var s = '   foo bar  The Quick Dog  is addicted to jumping  ';
var m = s.match(/[^ ]+( [^ ]+)*/g);
m && (m.join(', ') + '.'); // null OR join()
// prints "foo bar, The Quick Dog, is addicted to jumping."

match + join inside a function :

function fix(str, separator) {
    var m = str.match(/[^ ]+( [^ ]+)*/g);
    return m && (m.join(separator || ', ') + '.');
}

var s = ' ab cd   ef   gh ';
fix(s); // "ab cd, ef, gh."
fix(s, ' - '); // "ab cd - ef - gh."
fix(' '); // null