[英]Finding the next value of an array
Here I need to check whether the value comes after 1
is 1.1.
在这里,我需要检查值是否在
1
之后为1.1.
Next value comes after 1.1
is 1.2.
下一个值在
1.1
为1.2.
etc. 等等
The next value after a given value is takes by $C=$A[i]+'.'+$count;
给定值之后的下一个值为
$C=$A[i]+'.'+$count;
but when I print it prints values 1,2,3,4
etc. Is the way I have approached to the problem incorrect. 但是当我打印时,它会打印
1,2,3,4
等值。我解决该问题的方法是否正确。
<?
$A=array(1, 1.1, 1.2, 1.3, 1.4);
$count=0;
for($i=0;$i<sizeof($A);$i++){
$count++;
$B=$A[$count];
$C=$A[i]+'.'+$count;
if($B==$C){
//a code goes here
}
}
?>
You had a lot of syntax error, every variable in php must be prefixed with $. 您有很多语法错误,php中的每个变量都必须以$为前缀。 You missed that on the i-variable a couple of times.
您几次错过了i变量。 You also missed brackets in the for-loop.
您还错过了for循环中的括号。 And your $A variable was printed out because it was written before the PHP-tag.
$ A变量被打印出来,因为它是在PHP标记之前编写的。
I cleaned it up and corrected those issues: 我清理并纠正了这些问题:
$A = array(1, 1.1, 1.2, 1.3, 1.4);
$count = 0;
for($i = 0; $i < sizeof($A) - 1; $i++){
$count++;
$B = $A[$count];
$C = $A[$i] + 0.1;
if($B == $C){
// This will be executed every time the next value is "current + 0.1".
}
}
I hope this is what you are looking for. 我希望这是您要寻找的。
<?php
$a=array(1, 1.1, 1.2, 1.3, 1.4);
$count=0;
foreach($a as $v)
{
$c = "1".'.'.$count;
if($c==$v)
{
echo "Match Found";
}
$count++;
}
?>
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