C ++ 14结合了通用lambda和变量模板

Question

I know about generic lambdas , and I know about variable templates, but, what does this do? Is it even allowed?

template<typename T>
auto f = [](auto a, T b){ /**/ };

If it's allowed, can it be used as expected? That is, as f<type>(var_a, var_b) ?

Answer 1

A variable template must be declared constexpr . A lambda cannot occur in a constant-expression , so the initialisation is not allowed, and its operator() is not declared constexpr , so calling it isn't allowed.

In summary, this is ill-formed in the current C++14 draft.

Note: curiously, even though a lambda-expression cannot occur in a constant-expression , it seems that the closure type of a lambda may have a constexpr copy/move constructor.

Answer 2

该代码现在在C ++ 14的当前草案中是合法的，并且可以使用clang 3.5 trunk进行编译