jQuery load（）并传递到PHP GET并从#div获取数据

Question

I want to send request to PHP file, ie. ?page=1 and get the data from #div from the same php file, and do all using jquery .load();

I'm trying to do this like that:

$('#content_text').load("page1.php?page=1" + " #page1_tit");

And it doesn't work. I get no data inside #content_text and I have no errors in the console. Look's like ?page=1 request doesn't work. Anyone knows how to do that ?

This is the page1.php

<?PHP
if (isset($_GET['page'])) {
$i = $_GET['page'];

print $i;

include 'db.php';
    if ($db_found) {
    $SQL1 = "SELECT ID, content, tittle FROM pages WHERE ID = '$i'";
    $result = mysql_query($SQL1);

    while ( $db_field = mysql_fetch_assoc($result) ) {
    print "<div id=\"#page1_tit\">";
        print $db_field['tittle'];
    print "</div>";
    print "<div id=\"#page1_cont\">";
        print $db_field['content'];
    print "</div>";
    }
    mysql_close($db_handle);
    }
    print $i;
}
?>

Answer 1

看起来您的变量$ db_found ist为false或数据库查询返回0行，因此while不会运行。

Answer 2

<input type="button" id="pageloader" name="pageload">
<script type="text/javascript">
$(document).ready(function(){
$("#pageloader").click(function(){
$('#content_text').load("page1.php?page=1" + " #page1_tit");
});
});
</script>