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C ++帮助。 数组不适用于整数

[英]C++ Help. Arrays not working with integers

Here is my code: (C++) 这是我的代码:(C ++)

#include <iostream>
#include <stdlib.h>
using namespace std;
int main(){
    string sentence[9];
    string word[9];
    inb b[] = { 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 };
    int f = 0;
    for (int i = 1; i <= 10; i += 1){
        cin >> sentence[i - 1];
    }
    for (int a = 10; a > 1; a = a - b[f]){
        b[f] = 0;        
        int f = rand() % 10;
        b[f] = 1;
        word[f] = sentence[f];
        cout << world [f] << endl;
    }
}

However, when I run this I get a "runtime error". 但是,当我运行此程序时,出现“运行时错误”。 That's it, no line, no further error. 就是这样,没有一行,没有进一步的错误。 Nothing. 没有。

The Arrays in the bottom side of the code, like word[f] and b[f] do not work if I use f inside the "[]"'s. 如果我在“ []”的内部使用f,则代码底部的数组(如word [f]和b [f])将不起作用。

When I change all the "f"'s with [1] to test the code, it works. 当我用[1]更改所有“ f”以测试代码时,它可以工作。 But when I use "f"'s instead, it returns a runtime error. 但是,当我使用“ f”代替时,它将返回运行时错误。

Not sure if that is my compiler. 不知道那是我的编译器。 But hey - I am a 2 day old C++ coder. 但是,嘿-我是2天大的C ++编码器。

Your sentence is 9 "slots" big (addressed as sentence[0] to sentence[8] ). 您的sentence大了9个“插槽”(地址为sentence[0]sentence[8] )。 You try to put something in the 10th slot ( sentence[9] ), which is a no-no. 您尝试在第10个插槽中放入某些内容( sentence[9] ),这是禁止的。

(This pattern is repeated below with word .) (此模式在下面用word重复。)

You most likely want to declare those arrays as 10-element ones. 您最有可能希望将这些数组声明为10个元素的数组。

That's because sentence and word contain nine units. 这是因为sentenceword包含9个单位。 But rand()%10 will produce 9 , when you use word[f] = sentence[f] , word[9] and sentence[9] are out of range. 但是,当您使用word[f] = sentence[f]rand()%10将产生9 ,而word [9]和句子[9]不在范围内。 word[9] is the 10th element of array word . word[9]是数组word的第十个元素。

There are several problems with your code. 您的代码有几个问题。 Firstly, sentence and word only have 9 entries, but you try to use 10. Array declaration is 1-based, eg 首先,句子和单词只有9个条目,但是您尝试使用10。数组声明是基于1的,例如

char foo[2]; char foo [2];

declares two characters. 声明两个字符。 However, they are numbered 0 and 1, thus 但是,它们的编号为0和1,因此

char foo[2];
foo[0] = 'a'; //valid
foo[1] = 'b'; //valid
foo[2] = 'c'; //very bad.

this problem might be obfuscated for you by the fact that you are making 'b' an auto-sized array. 由于您正在使“ b”成为自动调整大小的数组,这一问题可能会使您感到困惑。

The second problem is that you declare 'f' twice. 第二个问题是您两次声明“ f”。

int f = 0;
for (int i = 1; i <= 10; i += 1){

and inside the loop 在循环内

    int f = rand() % 10;
    b[f] = 1;

Your for loop, then, is broken: 那么,您的for循环已损坏:

for (int a = 10; a > 1; a = a - b[f]){ for(int a = 10; a> 1; a = a-b [f]){

it uses the external 'f', which is always 0, to access element zero of b and subtract that from a. 它使用始终为0的外部“ f”访问b的元素零,并从a中减去该元素。

Here is how I would write the code you're trying to write: 这是我要编写的代码:

I honestly don't understand what your code is supposed to do, but here is how I might write a simpler version of the same thing: 老实说,我不明白您的代码应该做什么,但是这是我可能会写一个更简单的版本的方法:

#include <iostream>
#include <stdlib.h>
#include <array>

//using namespace std;  <-- don't do this.

int main(){
    std::array<std::string, 10> sentence;   // ten strings

    // populate the array of sentences.
    for (size_t i = 0; i < sentence.size(); ++i) {  // use ++ when ++ is what you mean.
        std::cin >> sentence[i];
    }

    for (size_t i = 0; i < sentence.size(); ++i) {
        size_t f = rand() % sentence.size(); // returns a value 0-9
        std::cout << sentence[f] << " ";
    }
    std::cout << std::endl;
}

Requires C++11 (-std=c++11 compiler option). 需要C ++ 11(-std = c ++ 11编译器选项)。 ideone live demo here ideone现场演示在这里

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