解析错误：语法错误，意外的'='，期望在第33行的DB_driver.php中出现T_FUNCTION

Question

Got a program that a coder designed but wasn't will to help setup it up. I am getting this error when trying to connect the code to the database

Parse error: syntax error, unexpected '=', expecting T_FUNCTION in \\system\\database\\DB_driver.php on line 33

I have double checked the hostname,username,password, and database name but with no victory.

var $hostname;      = 'localhost';
var $username;      = 'pepadmin';
var $password;      = '******';
var $database;      = 'databasetest';
var $dbdriver       = 'mysql';
var $dbprefix       = '';
var $char_set       = 'utf8';
var $dbcollat       = 'utf8_general_ci';
var $autoinit       = TRUE; // Whether to automatically initialize the DB
var $swap_pre       = '';
var $port           = '';
var $pconnect       = FALSE;
var $conn_id        = FALSE;
var $result_id      = FALSE;
var $db_debug       = FALSE;
var $benchmark      = 0;
var $query_count    = 0;
var $bind_marker    = '?';
var $save_queries   = TRUE;
var $queries        = array();
var $query_times    = array();
var $data_cache     = array();
var $trans_enabled  = TRUE;
var $trans_strict   = TRUE;
var $_trans_depth   = 0;
var $_trans_status  = TRUE; // Used with transactions to determine if a rollback should occur
var $cache_on       = FALSE;
var $cachedir       = '';
var $cache_autodel  = FALSE;
var $CACHE; // The cache class object

// Private variables
var $_protect_identifiers   = TRUE;
var $_reserved_identifiers  = array('*'); // Identifiers that should NOT be escaped

// These are use with Oracle
var $stmt_id;
var $curs_id;
var $limit_used;

Answer 1

first off, you probably don't need all those var declarations. also, you are terminating these lines with the semicolon before you even define them.

var $hostname;      = 'localhost';
var $username;      = 'pepadmin';
var $password;      = '******';
var $database;      = 'databasetest';

vs what you intended

$hostname      = 'localhost';
$username      = 'pepadmin';
$password      = '******';
$database      = 'databasetest';

Answer 2

remove semicolen after the variables try this

    var $hostname      = 'localhost';
    var $username     = 'pepadmin';
    var $password     = '******';
    var $database      = 'databasetest';

Answer 3

No need var and should not use semicolon before initializing variable. Remove the marked chars.

var $hostname ; = 'localhost';

var $username ; = 'pepadmin';

var $password ; = ' ** ';

var $database ; = 'databasetest';