从Python中的Gmail下载HTML

Question

I am attempting to download all emails from a certain sender in my gmail for analysis. I am running into an error on line 23.

Here is my code:

import imaplib
import email

mail = imaplib.IMAP4_SSL('imap.gmail.com')


username = raw_input('USERNAME (email):')
password = raw_input('PASSWORD: ')


try:
    mail.login(username, password)
    print "Logged in as %r !" % username
except imaplib.IMAP4.error:
    print "Log in failed."

mail.list()
# Out: list of "folders" aka labels in gmail.
mail.select("inbox") # connect to inbox.

fromWho = raw_input('FROM:')

result, data = mail.uid('search', None, '(FROM fromWho )') # search and return uids instead
latest_email_uid = data[0].split()[-1]
result, data = mail.uid('fetch', latest_email_uid, '(RFC822)')
raw_email = data[0][1]

Here is the error I am getting:

Traceback (most recent call last):
  File "test.py", line 23, in <module>

Any thoughts??

Answer 1

The IMAP4.uid works as command method, just using UIDs. The first part must be a command, that you have as search. Hence, the other parameters should be as the ones in the search method, just remember to quoute the names in the command string.

You should try something like

IMAP4.uid('SEARCH', None, '(FROM "{}")'.format(fromWho))