将for循环的输出分配给变量

Question

I am trying to assign the output of a for loop to a variable or dictionary, but as of right now i can only get it to print the first iteration of the loop and it's not even in the right format.

Here is my code:

result, data = mail.uid('search', None, "(FROM 'tiffany@e.tiffany.com')") # search and return uids instead
latest_email_uid = data[0].split()[-1]
result, data = mail.uid('fetch', latest_email_uid, '(RFC822)')
raw_email = data[0][1]

html = raw_email
soup = BS(html)
pretty_email = soup.prettify('utf-8')

urls={}
for x in soup.find_all('a', href=True):
    urls['href'] = x

print urls

I would like the format of the output of this to be how this code executes, but all this odes is print out the extracted links properly:

result, data = mail.uid('search', None, "(FROM 'tiffany@e.tiffany.com')") # search and return uids instead
latest_email_uid = data[0].split()[-1]
result, data = mail.uid('fetch', latest_email_uid, '(RFC822)')
raw_email = data[0][1]

html = raw_email
soup = BS(html)
pretty_email = soup.prettify('utf-8')

for urls in soup.find_all('a', href=True):
    print urls['href']

print urls

Thanks!

EDIT:

The way i would like it to print is this:

3D"http://elink.tiffany.com/r/YB7DL5S/32FU1/5A6EIF/QFMQOO/9SUZ8/52/h"=
3D"http://elink.tiffany.com/r/YB7DL5S/32FU1/5A6EIF/QFMQOO/N8ASK/52/h"=
3D"http://elink.tiffany.com/r/YB7DL5S/32FU1/5A6EIF/QFMQOO/DNH42/52/h"=
3D"http://elink.tiffany.com/r/YB7DL5S/32FU1/5A6EIF/QFMQOO/T2WPJ/52/h"=
3D"http://elink.tiffany.com/r/YB7DL5S/32FU1/5A6EIF/QFMQOO/PO7RQ/52/h"=
3D"http://elink.tiffany.com/r/YB7DL5S/32FU1/5A6EIF/QFMQOO/BRLMA/52/h"=
3D"http://elink.tiffany.com/r/YB7DL5S/32FU1/5A6EIF/QFMQOO/N8ASQ/52/h"=
3D"http://elink.tiffany.com/r/YB7DL5S/32FU1/5A6EIF/QFMQOO/SV4PN/52/h"=
3D"http://elink.tiffany.com/r/YB7DL5S/32FU1/5A6EIF/QFMQOO/RC53N/52/h"=
3D"http://elink.tiffany.com/r/YB7DL5S/32FU1/5A6EIF/QFMQOO/7Q3AA/52/h"=

with the solution below i ma getting this:

http://elink.tiffany.com/r/YB7DL5S/32FU1/5A6EIF/QFMQOO/1XF33/52/h?=' n:underline="" style='3D"text-decoratio='>click here, http://elink.tiffany.com/r/YB7DL5S/32FU1/5A6EIF/QFMQOO/6EN2U/52/h"=' target='3D"_blank"'>http://eimg.tiffany.com/mbs_tiffanyc/Standard/Logoblue.gif"' title='3D"Tiffany' wi="dth=3D147"/>, http://elink.tiffany.com/r/YB7DL5S/32FU1/5A6EIF/QFMQOO/T2WUY/52/h"=' lucida="" sans="" style='3D"text-decoration:none;' unicode="">ENGAGEMENT,

Answer 1

You are creating a dict with just one key which you overwrite for each iteration of the loop. Maybe a list makes more sense?

urls = []
for x in soup.find_all('a', href=True):
    urls.append(x)

Answer 2

You keep assigning to a same key in the dict, that's your only mistake:

Collect and put it into a list:

urls=[]
for x in soup.find_all('a', href=True):
    urls.append(x['href'])
print urls

Or into a dictionary:

urls={}
search = soup.find_all('a', href=True)
for x in range(len(search)):
    urls[x] = search[x]['href'] ##Result is: {0:firsturl, 1:secondurl, 2:thirdurl}
    ##and so on

This should work as you want it, hope this helps!