C：警告：格式'％s'需要匹配的'char *'参数

Question

I'm currently working on File I/O and I tried using this function:

fprintf (FILE *pFile, char *pFormat, <variable list>);

with my variables

fprintf ( filePtr, "\"%s\"n", myarray );

My compiler issues a warning that says warning: format '%s' expects a matching 'char *' argument but I have declared myarray as char *myarray = "This is a string" . Can anyone tell me what went wrong? My code is:

#include <stdio.h>
int main ()
{
FILE *filePtr;
char *myarray = "This is a string";

if ((filePtr = fopen("sample.dat", "w")) == NULL) {
   printf ("File could not be opened.\n");
} else {
   printf ("This will print the string onto file:\n");

   while (!feof(filePtr)) {
      fprintf ( filePtr, "\"%s\"", myarray );
   }
}
fclose (filePtr);
return 0;
}

Answer 1

I tried to compile with gcc, it found another issue - missing argument in the fopen:

 if ((filePtr = fopen("sample.dat")) == NULL) {

So, need to use:

 if ((filePtr = fopen("sample.dat", "r")) == NULL) {

Thereafter, code compiled without problem. Compiler version:

gcc version 4.2.1 20070831 patched [FreeBSD]