Python Popen找不到指定的文件

Question

I have the following code

pathToFile = "R:\T2 Output\12345--01--Some File 1--ABCD.mp4"
process = subprocess.Popen(['ffprobe.exe', '-show_streams', '"'+pathToFile+'"'],
    shell=True, stdout=subprocess.PIPE, stderr=subprocess.PIPE)

I get the error:

[Error 2] The system cannot find the file specified

What I have tried:

• Changing shell=True to shell=False
• Combining the command into a single string instead of using a list (I even print it to screen, and I can copy and paste into a command prompt where the file runs and gives the expected output (no error)
• I made sure that ffprobe.exe is located in the PATH and can be executed from the command line without specifying a directory

Things of note:

• The file is located on a mapped network drive (R)
• The file has spaces in the filename, this is why I surrounded it by quotes.

I'm sure I'm missing something simple. Can anyone point me in the right direction? I've done quite a lot of searching on this site and others and trying suggestions.

Answer 1

\\符号在python中算作转义字符，使用r可以将其关闭：

pathToFile = r"R:\T2 Output\12345--01--Some File 1--ABCD.mp4"