将字符串分配给String数组

Question

I am trying to assign each string a user inputs to a String array. The entire thing is in a for loop and is evaluated by the index of the array. My code is:

String skillAssign[] = new String[100];

    for (int i=0; isDone == false; i++)
    {
        System.out.println(skillAssign[i]);
        System.out.println(i);
        skillAssign[i] = keyboard.nextLine();
        if ((!(skillAssign[i].equalsIgnoreCase("stats"))) && (!(skillAssign[i].equalsIgnoreCase("done"))))
        {
            assignmentValue = keyboard.nextInt();
            if (((skillAssign[i].equalsIgnoreCase("health"))) && (skillPoints - assignmentValue >=0))
            {
                System.out.println("Added " + assignmentValue + " points to Health!");
                skillPoints = (skillPoints - assignmentValue);
                newMaxHealth = (assignmentValue + newMaxHealth);
            }
        //code that evaluates the string located inside the skillAssign[i] for other stats
    }

The first string evaluates properly, but when I go to input the second string, I get java.util.InputMisMatchException. How can I get it so it assigns a string to each index of the array inputted by the user, then evaluate it? (I think I got the evaluation part though)

I tried to limit the post to relevant code, so things like isDone are omitted, but isDone is changed to true when done is typed and keyboard is constructed with Scanner keyboard = new Scanner all other variables are set to 0 except for skillPoints

Answer 1

I have tested the abovementioned code, and this is what happens:

• We enter the loop.
• You are requested to input the first string (through keyboard.nextLine() ). I inputted ' health '.
• You are requested to input an integer (through keyboard.nextInt() ). I inputted ' 40 '.
• We re-enter the loop.
• You are requested to input an integer (through keyboard.nextInt() ).
• ...

It seems that I'm not asked to input the second string, but instantly the integer.

I do not know why it is, but it looks like nextInt() causes the next nextLine() to be skipped.

Maybe you can replace

assignmentValue = keyboard.nextInt();

with

try {
    assignmentValue = Integer.parseInt(keyboard.nextLine());
}
catch (NumberFormatException exc) {
    throw new InputMismatchException(exc.getMessage());
}

---

EDIT
I saw a post on StackOverflow which briefly mentions why nextLine() after nextInt() is skipped.

Answer 2

i believe this is closer to your intention. this way the reference to your keyboard input that nextLine grabs isn't lost on each iteration, but remains preserved in a new String instance. correct?

System.out.println(i);
String getMe = keyboard.nextLine();
skillAssign[i] = new String(getMe);
System.out.println(skillAssign[i]);