[英]PHP Decode JSON variables
I have the following json file below that outputs the following information: 我在下面的以下json文件中输出以下信息:
stdClass Object
(
[status] => OK
[droplet] => stdClass Object
(
[id] => 567894
[name] => Luna
[created_at] => 2013-10-10T18:13:08Z
)
)
I'm trying to get the [name] and save it to a variable called $serverName. 我正在尝试获取[名称]并将其保存到名为$ serverName的变量中。 I've tried using the code below but have no luck :/
我尝试使用下面的代码,但没有运气:/
<?php
$request = 'Link to JSON FILE';
$response = file_get_contents($request);
$jsonobj = json_decode($response);
$serverName = $jsonobj->name;
I've tried looking online but I'm having troubles getting this to work :/ 我曾尝试过在网上寻找内容,但无法正常工作:/
Thanks a ton <3 吨<3
Got it to work. 得到它的工作。 Just need to do;
只需要做;
$jsonobj->droplet->name;
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