python sage从命令行附加并运行另一个命令

Question

I want to load a sage file and run a function from that file, all from bash.

The attach command is giving me trouble...

This works:

bash-prompt$ sage -c "print 2; print 3"
2
3
bash-prompt$

This also works:

bash-prompt$ sage -c "attach somefile.sage"
some print just to confirm the file is loaded
bash-prompt$

But this doesn't work:

bash-prompt$ sage -c "attach somefile.sage; print 3"
python: can't open file '/path/to/somefile.sage; print Integer(3)': [Errno 2] No such file or directory

How can I get this to work, or what can I do instead?

Answer 1

If it helps someone...

I ended up using this monstrosity:

sage somefile.sage && sage -python -c "execfile('somefile.py'); wrapper()" && rm somefile.py

Ok, the rm part is not really all that necessary :)

Answer 2

我认为最简单的方法是在实际的Sage文件的最后一行调用该函数：例如，“ somefile.sage”的最后一行print 3 。