具有抽象类的C ++ 11对象组合

Question

Let's say I have a class Foo that has a const member of an abstract class Bar, what is the correct way to pass Bar in the constructor to initialize the const member?

class Foo
{
public:
    Foo(?Bar? bar): bar(?bar?) {};
private:
    const ?Bar? bar;
}

In C++11 I was thinking of using std::unique_ptr like so:

class Foo
{
public:
    Foo(std::unique_ptr<Bar> &bar): bar(std::move(bar)) {};
private:
    const std::unique_ptr<Bar> bar;
}

Is this the best way to do it? What are the other ways and when should I use them?

Answer 1

In...

struct Foo
{
public:
    Foo(std::unique_ptr<Bar> &bar): bar(std::move(bar)) {};
    const std::unique_ptr<Bar> bar;
};

... bar (the pointer) is not modifiable, but the value to which is points is.

Is this what you want?

I would rather think:

class Foo
{
public:
    Foo(std::unique_ptr<const Bar>& bar): bar(std::move(bar)) {}

private
    std::unique_ptr<const Bar> bar;
};

would be more appropriate, as not the value is truly constant. I suspect that this won't compile because the unique_ptr cannot call the destructor (specification of custom deleter springs to mind), but the value to which bar points is const, which is what you really want (I suspect).