[英]Callbacks in C# taking the callback directly in the method like in javascript
I have the function in javascript which is something like 我在javascript中有函数,就像
dothis(variablea, function(somevalue) {
..
});
which comes from function dothis(variablea, callback) {..}
来自
function dothis(variablea, callback) {..}
So I want to fire dothis
then callback the callback function later, when I get a response from a server. 所以我想触发
dothis
然后在服务器收到响应时回调回调函数。
How would I go about implementing something like this in C#, I've had a look at a couple of examples but I would like to pass the callback function directly into the method. 我将如何在C#中实现类似的功能,我看了几个示例,但我想将回调函数直接传递给方法。 Is this possible?
这可能吗?
Absolutely - you basically want delegates . 绝对-您基本上需要代表 。 For example:
例如:
public void DoSomething(string input, Action<int> callback)
{
// Do something with input
int result = ...;
callback(result);
}
Then call it with something like this: 然后用类似这样的名称来调用它:
DoSomething("foo", result => Console.WriteLine(result));
(There are other ways of creating delegate instances, of course.) (当然,还有其他创建委托实例的方法。)
Alternatively, if this is an asynchronous call, you might want to consider using async/await from C# 5. For example: 或者,如果这是一个异步调用,则可能要考虑使用C#5中的async / await。例如:
public async Task<int> DoSomethingAsync(string input)
{
// Do something with input asynchronously
using (HttpClient client = new HttpClient())
{
await ... /* something to do with input */
}
int result = ...;
return result;
}
The caller can then use that asynchronously too: 然后,调用者也可以异步使用它:
public async Task FooAsync()
{
int result1 = await DoSomethingAsync("something");
int result2 = await AndSomethingElse(result1);
Console.WriteLine(result2);
}
If you're basically trying to achieve asynchrony, async/await is a much more convenient approach than callbacks. 如果你基本上要达到异步,异步/等待比回调一个更加方便的方法。
You're looking for delegates and lambda expressions: 您正在寻找委托和lambda表达式:
void DoSomething(string whatever, Action<ResultType> callback) {
callback(...);
}
DoSomething(..., r => ...);
However, you should usually return a Task<T>
instead. 但是,通常应该返回
Task<T>
。
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