[英]How to use grep with quotes inside a shell script?
I am trying to use the following pattern inside a shell script eg. 我正在尝试在shell脚本中使用以下模式。 I want to use the following:
我要使用以下内容:
grep ^"#" $fn | grep -v NM$ > $op
but inside bash
script. 但在
bash
脚本中。 The problem is normally bash
considers everything after the "#" as a comment. 问题通常是
bash
将“#”之后的所有内容都视为注释。 If i use 如果我用
grep ^"\#" $fn
I think it changes the meaning. 我认为这改变了含义。 I am a newbie.
我是新手。
Any help will be appreciated. 任何帮助将不胜感激。
There are multiple possibilities: 有多种可能性:
grep '^#' $fn
or 要么
grep "^#" $fn
or 要么
grep ^\# $fn
Here is a little example which I saved as foo.sh
这是我保存为
foo.sh
一个小示例
echo "#"
echo '#' # this is a comment
echo '\#'
when run as sh foo.sh
this is what is printed out 当以
sh foo.sh
运行时,这就是打印出来的内容
#
#
\#
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