Unix Shell脚本

Question

I've a situation, where I've a source file and a target file, supposed to be similar. The source file has sets of information like below. I need to compare each set of information in Source and Target files. If anything's missing in Target file, I need to write the line into the target file. I could have matched line by line, but the sets of Source and target files are not in order. Please help me how to achieve using a shell script.

Source file:

[Set.1]
value=1
date=today

[Set.2]
value=2
date=today

Target File:

[Set.2]
value=2

[Set.1]
value=1
date=today

If you can see, date is missing in [Set.2] of target file, so, I need to copy it from Source File.

Answer 1

如果file_set1中存在file_set2中缺少的任何内容，将通过file_set2和file_set1下面的命令进行比较，然后将其复制回file_set2。

awk 'FNR==NR{a[$0];next}!($0 in a)' file_set2 file_set1 >>file_set2

Answer 2

你可以尝试使用rsync

rsync /target/file/path /source/file/path 

Answer 3

This is either a very easy problem or a hard one. If you just need to make the files identical then

cp source_file target_file

would be enough. But it seems like you want to keep the ordering of sections in target_file unchanged. This will require you to parse the files first and remember the order of the sections.

Since this is Windows INI file format, the ordering of sections should not be significant to the program reading it. Check to make sure whether the reader actually cares.