捕获并导出多个命名组到csv

Question

I'd like to capture two particular data from the input files using regular expressions like this:

$reg = [regex]"(?<Name>^Name:.*)|(?<Id>^Id:.*)"
gci C:\test\*.txt | Get-Content | Select $reg -allmatches | Select -Expand Matches|
...
new-object psobject -property @{Name=$n; Id=$i}
...
Select-Object Name, Id | Export-Csv c:\info.csv –NoTypeInformation

The problem I faced is some files don't have 'Id' entry. If any file doesn't have the 'Id' entry in it, it doesn't show up in the exported csv file. I'd greatly appreciate if someone could help me come up with the solution.

C:\\test\\file1.txt contains:

Name: Sturgeon Ocean   
Alias: Socean   
Id: 384932   
Address: 3600 Caviar  
Street, Pacific beach   
...   
Cell: 389-394-3843   
...  

Answer 1

Not tested, but I think this should work:

Foreach ($file in gci C:\test\*.txt)
 { 
   $Record = New-object PSObject -Property @{Name=$null;ID=$null}
   Foreach ($line in Get-Content $file.FullName)
    {
      switch -Regex ($_)
      {
       '^Name' {$Record.Name = ($_ -replace '^Name:(.+)$','$1').Trim()}
       '^ID'   {$Record.ID   = ($_ -replace '^ID:(.+)$','$1').Trim()}
      }
    }
    $Record
 }

No switch

$reg = [regex]"(^Name:.*)|(^Id:.*)"

gci c:\new*.txt | 
foreach {
          $matched = (gc reg_test0.txt) -match $reg -replace '^.+:\s*',''
           new-object psobject -Property @{Name=$matched[0];ID=$matched[1]} 
        }| Select Name,Id | Export-Csv c:\new\info.csv -NoTypeInformation