如何拆分“1 $$$$”使用awk

Question

if I have a string like "sn":"1$$$$12056597.3,2595585.69$$", how can I use awk to split "1$$$$"

I tried

**cat $filename | awk -F "\"1\$\$\$\$" '{ print $2 }'**
**cat $filename | awk -F "\"1$$$$" '{ print $2 }'**

but all failed

Answer 1

any number of $ use

echo '"1$$$$12056597.3,2595585.69$$"' | awk -F '"1[$]+' '{ print $2 }'

exactly 4 use

echo '"1$$$$12056597.3,2595585.69$$"' | awk -F '"1[$]{4}' '{ print $2 }'

to help debug problems with escape characters in the shell you can use the built-in shell command set which will print the arguments that are being passed to awk after the shell has interpreted any escape characters and replaced shell variables

In this case the shell first interprets \\$ as an escape for a plain $

set -x
echo '"1$$$$12056597.3,2595585.69$$"'|awk -F "\"1\$\$\$\$" '{ print $2 }'
+ echo '"1$$$$12056597.3,2595585.69$$"'
+ awk -F '"1$$$$' '{ print $2 }'

You can use \\$ so the \\$ get to awk, but \\$ is interpreted in awk regular expressions as a $ anyway. At least awk is nice enough to warn you...

echo '"1$$$$12056597.3,2595585.69$$"'|awk -F "\"1\\$\\$\\$\\$" '{ print $2 }'
+ echo '"1$$$$12056597.3,2595585.69$$"'
+ awk -F '"1\$\$\$\$' '{ print $2 }'
awk: warning: escape sequence `\$' treated as plain `$'

Turn off debugging with

set +x

Answer 2

echo '"1$$$$12056597.3,2595585.69$$"' | awk -F '"1[$]+' '{ print $2 }' |sed 's/.\{3\}$//'

Or if you want to split both float digit:

echo '"1$$$$12056597.3,2595585.69$$"' | awk -F '"1[$]+' '{ print $2 }' |sed 's/.\{3\}$//' |awk 'BEGIN {FS=","};{print $1}'

And

echo '"1$$$$12056597.3,2595585.69$$"' | awk -F '"1[$]+' '{ print $2 }' |sed 's/.\{3\}$//' |awk 'BEGIN {FS=","};{print $2}'