MySql获取加扰结果

Question

Current scenario :

I have a MySQL database (products_db) with product links ('links') . Now the products / links are from 11 different websites (advertisers).

Is there some sort of MySQL query I can make to get the results in groups of 11 links, one link for each website ?

The point is to get a list of results with all the links, one link for each 11 website .

I know I can use the following to get the first 11 rows each from a different website, but I need ALL the results arranged like that .

SELECT id, name, advertiser, link
FROM table
GROUP BY advertiser

If not, I guess I have to go back to sort the list in PHP ..

thanks!

Answer 1

使用group by而不是order by ：

SELECT id, name FROM table GROUP BY id