正则表达式转义空格和特殊字符

Question

I'm getting a console error:

Cannot call method 'replace'

What I wanted to achieve is to escape all special characters and spaces.

text.replace(/[.*+?^${}()|[\]\/\\]/g, '\\$0');

So, when I have a string

"dfgsdfgsdfg) )( &( ^)( )& dfgdg123123sdfg"

it should be read only as "dfgsdfgsdfgdfgdg123123sdfg"

Note: I want to escape/ignore all non-alphanumeric characters and that includes spaces. It should only be [a-zA-Z0-9]

PS newbie in regex.

Answer 1

Probably the best approach is to match for "not alphanumeric", like so:

var text="dfgsdfgsdfg))(&(^)()& dfgdg123123sdfg";
alert(text.replace(/[^a-zA-Z0-9]/g, ''));

JS Fiddle Demo

Answer 2

Try this instead.

text.replace(/[-[\]{}()*+?.,\\^$|#\s]/g, "\\$&");

Or just match any non-word character which would be the best approach for this.

text.replace(/\W/g, '');

Answer 3

Try this:

$(document).ready(function(){
 var str = "dfgsdfgsdfg))(&(^)()& dfgdg123123sdfg";
alert(str.replace(/[&/\#,+()$~%.'":*?<>{}^ ]/g, ""));
});

DEMO