[英]Encode then decoded in base64 doesn't output my input arraybuffer
Given the two functions below that I use to encode and decode in base64. 鉴于我用于在base64中编码和解码的两个函数。 If I encode then decode, I just do this, then I don't get the same values between my ouput and my input.
如果我编码然后解码,我只是这样做,然后我没有在我的输出和我的输入之间获得相同的值。
Any idea what I'm doing wrong ? 知道我做错了什么吗?
function _base64ToArrayBuffer(string_base64) {
var binary_string = window.atob(string_base64);
var len = binary_string.length;
var bytes = new Uint8Array( len );
for (var i = 0; i < len; i++) {
var ascii = string_base64.charCodeAt(i);
bytes[i] = ascii;
}
return bytes.buffer;
}
function _arrayBufferToBase64( array_buffer ) {
var binary = '';
var bytes = new Uint8Array( array_buffer );
var len = bytes.byteLength;
for (var i = 0; i < len; i++) {
binary += String.fromCharCode( bytes[ i ] )
}
return window.btoa( binary );
}
var input = my_ArrayBuffer;
var raw_data_base64 = _arrayBufferToBase64(input);
var ouput = _base64ToArrayBuffer(raw_data_base64);
Your line number 6 你的第6行
var ascii = string_base64.charCodeAt(i);
should be 应该
var ascii = binary_string.charCodeAt(i);
Your problem is in _base64ToArrayBuffer
您的问题出在
_base64ToArrayBuffer
for (var i = 0; i < len; i++) {
var ascii = string_base64.charCodeAt(i); // THIS LINE
bytes[i] = ascii;
}
If you think about what the ArrayBuffer you're getting back actually means (in terms of charcodes) it was giving you back your Base64 String . 如果你考虑一下你所获得的ArrayBuffer实际意味着什么(就charcodes而言)它会让你回到你的Base64字符串 。
Looks like you actually wanted to use 看起来你真的想用
binary_string.charCodeAt(i);
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