使用sublime文本和正则表达式匹配一行中的第一个空格

Question

So regular expressions have always been tough for me. Im getting frustrated trying to find a regular expression that will select the first white space on a line. So then i can use sublime text to replace that with a /

If you could give a quick explanation that would help to

Answer 1

In the spirit of @edi's answer, but with some explanation of what's happening. Match the beginning of the line with ^ , then look for a sequence of characters that are not whitespace with [^\\s]* or \\S* (the former may work in more editors, libraries, etc than the latter), then find the first whitespace character with \\s . Putting these together, you have

^[^\s]*\s

You may want to group the non-whitespace and whitespace parts, so you can do the replacement you're talking about:

^([^\s]*)(\s)

Then the replacement pattern is just \\1/

Answer 2

你可以使用这个正则表达式。

^([^\s]*)\s