[英]XOR two blocks in python
i am new to programming in python...i want to make XOR between 2 blocks here is my code 我是python编程的新手...我想在2个块之间进行XOR,这是我的代码
def XorBlock(block1, block2):
l = len(block1);
if (l != len(block2)):
raise ValueError, "XorBlock arguments must be same length"
return [(block1[j]+block2[j]) % 2 for j in xrange(l)];
but when i call it gives me 但是当我打电话给我的时候
TypeError: not all arguments converted during string formatting
so please anyone help me where is the bug in this code..thanks in advance 所以请任何人帮助我这段代码中的错误在哪里..提前谢谢
Perhaps this is what you're looking for: 也许这就是您要寻找的:
def XorBlock(block1, block2):
l = len(block1)
if l != len(block2):
raise ValueError
# |-> Converting into int
return [(int(block1[j])+int(block2[j])) % 2 for j in xrange(l)]
# |-> Converting into int
if __name__ == '__main__':
print XorBlock("12345", "23456")
>>> XorBlock("010101", "108734")
[1, 1, 0, 0, 1, 1]
I decided that keeping both arguments as strings would be best, as in binary, you may have to have some 0
s before any digits of value. 我决定最好将两个参数都保留为字符串,因为在二进制中,您可能必须在值的任何数字前加上0
s。
This part is wrong, take a look: 这部分是错误的,看一下:
(block1[j]+block2[j]) % 2
both items are string, therefore, the result is a string. 这两个项目都是字符串,因此结果是字符串。 In short, python treats your %2
as a string formatting command. 简而言之,python将您的%2
视为字符串格式命令。
"string"%something
will expect the string to specify where it should format something
. 将期望字符串指定应该格式化something
。 If it doesn't specify anything, the current TypeError
will be raised. 如果未指定任何内容,则将TypeError
当前的TypeError
。 What you probably need is something like this: 您可能需要的是这样的东西:
return[(int(block1[j])+int(block2[j])) % 2 for j in xrange(l)]
#This converts it to integers, then xor it.
Hope this helps! 希望这可以帮助!
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