在SQL Server 2008 R2中取整

Question

I have this query

(case when a.item_no >= '77000' and a.item_no <='77099' then
    (op_drill + op_machine + op_ssd + op_freight + op_paint + ((actual_tooling * 1.2))) 
    else (op_drill + op_machine + op_ssd + ((op_drill + op_machine + op_ssd) *.27) + ((op_drill + op_machine + op_ssd + op_freight + (op_curforg *1.25) + ((op_drill + op_machine + op_ssd)*.27)) * .075)+
     op_freight + (op_curforg *1.25) + op_paint) 
      end)  as new_cost,

it returns 10.1201575

In vb.net I can run this statement

 dblNewCost = Math.Round(dblNewCost, 2, MidpointRounding.AwayFromZero)

which returns 10.13

Is there a way to duplicate this is sql server. I tried round(num,2) but that didn't showup correctly

Answer 1

I think you have some other issue. SQL Servers ROUND() function works just like VB's. There is no way using Math.Round(10.1201575, 2, MidpointRounding.AwayFromZero) would return 10.13. Compare the number that is being rounded on both side to make sure you are comparing apples-to-apples.