[英]How to free a linked list?
I have created a linked list in a function and throughout the rest of the program I am accessing the list using a pointer. 我已经在一个函数中创建了一个链表,在程序的其余部分中,我都使用指针来访问链表。 Now how would I free this linked list at the end of my program? 现在如何在程序结束时释放此链接列表? Do I plainly use free(CircuitData)
or do I have to run through the list freeing each node? 我是简单地使用free(CircuitData)
还是必须遍历列表以释放每个节点? Writing this I'm thinking freeing each node is the obvious answer... 写这篇文章我想释放每个节点是显而易见的答案...
On a side note I'd also like to ask how to find out whether all memory allocated during a program is freed properly? 附带一提,我还想问一问如何找出在程序执行期间分配的所有内存是否正确释放?
ListNodeType *CircuitData;
CircuitData = NULL;
ReadFile(&CircuitData, &numEl, &numNodes);
void ReadFile(ListNodeType **CircuitData, int *numEl, int *numNodes){
ListNodeType *newPtr, *tempPtr;
newPtr = malloc(sizeof(ListNodeType));
*CircuitData = newPtr;
newPtr->nextPtr = NULL;
//MORE CODE
I would think of something like this: 我会想到这样的事情:
struct node
{
int data;
node* next;
} *head;
void deleteAllNodes(node* start)
{
while (start != NULL)
{
node* temp = start;
start = start -> next;
free(temp);
}
}
I think you can do something like this : 我认为您可以执行以下操作:
void freeFunction(ListNodeType *CircuitData)
{
void *victim;
while (CircuitData)
{
victim = CircuitData;
CircuitData = CircuitData->next;
free(victim);
}
}
For your first question, yes, you should walk the list and free
each node. 对于第一个问题,是的,您应该遍历列表并free
每个节点。
The second question is a bit harder to answer. 第二个问题很难回答。 If you have an object in memory, but no way to access it, that's a memory leak. 如果您在内存中有一个对象,但无法访问它,则是内存泄漏。
There are tools you can use to analyze your memory pool. 您可以使用一些工具来分析内存池。 Check out valgrind: 查看valgrind:
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