PowerShell：以长数组的形式编写Export-csv属性

Question

Following is an example of my code:

---

$logpath = @(gci -path "c:\logs")
foreach ($i in $logpath)    
        {
        [array]$n += ($i.tostring()).trimend(".log")
    [array]$t += ($i.tostring()).lastwritetime
    }
$obj = new-object psobject
$obj | Add-Member -MemberType NoteProperty -Name Logname -Value $n
$obj | Add-Member -MemberType NoteProperty -Name LastWriteTime -Value $t
$i | export-csv c:\temp\logs.csv

---

Following is what the output looks like:

Name,LastWriteTime  
----,-------------
Value1...,Value1

---

Following is what I want it to look like:

Name,LastWriteTime  
Value1,Value1
Value2,Value2

Answer 1

Just to use your code can you try this :

$logpath = @(gci -path "c:\logs")
$objects = @() # Empty array
foreach ($i in $logpath)    
{
  $n = ($i.tostring()).trimend(".log")
  $t = ($i.tostring()).lastwritetime

  $obj = new-object psobject
  $obj | Add-Member -MemberType NoteProperty -Name Logname -Value $n
  $obj | Add-Member -MemberType NoteProperty -Name LastWriteTime -Value $t
  $objects += $obj
}

$objects | export-csv c:\temp\logs.csv

I just use an array of objects inside the loop.

Answer 2

There's a basename property you can use in lieu of trimming off the file extensions:

gci -path "c:\logs" |
select @{l='Name';e={$_.basename}},Lastwritetime |
export-csv c:\temp\logs.csv

Answer 3

You're trying too hard. Simply use a pipeline, select the desired properties, then export the result to a CSV:

$logFolders = 'C:\logs', 'D:\more\logs', 'H:\some\other\logs'
gci -Path $logFolders `
  | select @{n='Logname';e={$_.Name.TrimEnd(".log")}}, LastWriteTime `
  | Export-Csv 'C:\temp\logs.csv'