[英]How to properly use a boolean in a method and print result
I am working on a program and I am almost finished with it. 我正在开发一个程序,几乎完成了。 The only thing I can't figure out is how to as the user for ay or n and then display the boolean in the program to be true or false.
我唯一不知道的是如何以ay或n为用户,然后在程序中显示布尔值是true还是false。 It keeps giving me an error.
它一直给我一个错误。 Here is the code that I am working with.
这是我正在使用的代码。 I just want it to display true or false when the last print statement in the driver executes.
我只希望它在驱动程序中的最后一个打印语句执行时显示true或false。 Thank you
谢谢
public class Customer extends Person {
protected int customerNum;
protected boolean mailingList;
protected char answ;
public Customer() {
super();
// TODO Auto-generated constructor stub
}
public Customer(String name, String address, double telephone,
int customerNum, boolean mailingList) {
super(name, address, telephone);
this.customerNum = customerNum;
this.mailingList = mailingList;
}
/**
* @return the customerNum
*/
public int getCustomerNum() {
return customerNum;
}
/**
* @param customerNum the customerNum to set
*/
public void setCustomerNum(int customerNum) {
this.customerNum = customerNum;
}
/**
* @return the mailingList
*/
public boolean isMailingList() {
return mailingList;
}
/**
* @param mailingList the mailingList to set
*/
public void setMailingList(boolean mailingList) {
try {
if(answ == 'y'){
mailingList = true;
}
else if(answ == 'n')
mailingList = false;
this.mailingList = mailingList;
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
/* (non-Javadoc)
* @see java.lang.Object#toString()
*/
@Override
public String toString() {
return "Customer [customerNum=" + customerNum + ", mailingList="
+ mailingList + "]";
}
And then the driver 然后是司机
import java.util.Scanner;
public class CustomerDriver extends PreferredCustomer {
/**
* @param args
*/
public static void main(String[] args) {
Scanner kb = new Scanner(System.in);
PreferredCustomer customer1 = new PreferredCustomer();
System.out.println("Enter Customer Name: ");
customer1.setName(kb.nextLine());
System.out.println("Enter Customer Address: ");
customer1.setAddress(kb.nextLine());
System.out.println("Enter Telephone Number: ");
customer1.setTelephone(kb.nextDouble());
System.out.println("Enter the Customer Number: ");
customer1.setCustomerNum(kb.nextInt());
System.out.println("Does customer wish to be on mailing list? \n" +
"Enter 'y' for yes and 'n' for no: ");
customer1.setMailingList(kb.nextBoolean());
System.out.println("Enter amount of Customer's Purchase: ");
customer1.setPurchases(kb.nextDouble());
System.out.println("Customer's Discount is as follows: " + customer1.getDiscountLevel() + "\n");
System.out.println("Customers Name: " + customer1.getName() + "\nCustomers Address: " + customer1.getAddress() + "\nCustomers Phone" + customer1.getTelephone() +
"\nCustomer Number: " + customer1.getCustomerNum() + "\nMailing List Preferrence: " + customer1.isMailingList() + "\nCustomer's Purchase Amount " +
customer1.getPurchases() + "\nCustomers Discount Rate (if any) :" + customer1.getDiscountLevel());
// TODO Auto-generated method stub
}
} }
You can only use nextBoolean()
when the token is literally "true" or "false" . 仅当标记字面意义上为“ true”或“ false”时,才可以使用
nextBoolean()
。 Otherwise, it'll throw an InputMismatchException. 否则,它将引发InputMismatchException。 The answers "y" and "n" don't count.
答案“ y”和“ n”不计算在内。 You either need to prompt for the literal values "true" or "false" or else read the y/n response as a String and convert to a boolean yourself, like:
您要么需要提示输入文字值“ true”或“ false”,要么将y / n响应读取为String并自己转换为布尔值,例如:
String yOrN = kb.next();
if ("y".equals(yOrN)) customer1.setMailingList(true);
Update: I see now that you already have the "if answer == 'y'" logic in your setMailingList()
method. 更新:我现在看到您在
setMailingList()
方法中已经具有“ if answer =='y'”逻辑。 However, you're trying to pass a boolean to that method and then change the value of that boolean based on the value of the answ
field, which is never assigned a value. 但是,您尝试将布尔值传递给该方法,然后根据
answ
字段的值更改该布尔值,该字段从未分配值。 You need to work on that part of the code before it'll work, too. 您还需要先处理代码的这一部分,然后才能起作用。 I'd say you're correct to be passing a boolean to that method, so the "y or n" logic should move out of it to your main method.
我会说您将布尔值传递给该方法是正确的,因此“ y或n”逻辑应该移出它到您的main方法。
y
and n
are not valid Booleans
. y
和n
是无效的Booleans
。 You would need to input true
or false
for it to work. 您需要输入
true
或false
才能使其正常工作。
Your best bet would be to do something like this: 最好的选择是执行以下操作:
if (kb.nextLine().equals("y")) {
customer1.setMailingList(true);
} else {
customer1.setMailingList(false);
}
you are asking user to enter char input 'y' or 'n', but your code is actually expecting 'true' or 'false' 您正在要求用户输入字符输入“ y”或“ n”,但是您的代码实际上期望的是“ true”或“ false”
customer1.setMailingList(kb.nextBoolean()); customer1.setMailingList(kb.nextBoolean());
you may want to change it to take string input from user and check 您可能需要更改它以接受用户的字符串输入并检查
System.out.println("Does customer wish to be on mailing list? \n" +
"Enter 'y' for yes and 'n' for no: ");
customer1.setMailingList(kb.nextBoolean());
Here you're asking user to enter a character y
or n
. 在这里,您要求用户输入字符
y
或n
。 When you're calling nextBoolean
, you're requesting a boolean input. 调用
nextBoolean
,您需要一个布尔输入。 Neither y
or n
is a boolean. y
或n
都不是布尔值。 A boolean
is either true
or false
. boolean
是true
还是false
。 Instead, prompt the user to enter true
or false
instead of y
or n
. 而是提示用户输入
true
或false
而不是y
或n
。 Or explicitly make y
= true
and n
= false; 或者明确地使
y
= true
和n
= false;
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