Java将字符串转换为十进制（ASCII）？

Question

String buffer = "c";

Conversion by Decimal. I wanna change buffer value to decimal value.

In ASCII Table
DEC     HEX     CHAR
 99      63      c

So, Finally buffer -> 99 ( return value int or String and something )

How Can I Change that value?

Integer.parseInt(buffer, 12) -> returns 12

But I wanna get 99

is it Possible to conversion?

Answer 1

String buffer = "c";
char ch = buffer.charAt(0);
System.out.println((int)ch);

This should do it.

Answer 2

try

System.out.println((int)ch);

where ch is a char

Of course in you code you have a string, so maybe you need to get the first char or something

Answer 3

String buffer = "abc";
for(int i=0;i<buffer.length();i++)
{
    System.out.println((int)buffer.charAt(i));
}