[英]Submitting form by jquery using method=post
i want to submit a form by jquery. 我想通过jQuery提交表格。 i write the query form as follow 我写查询表格如下
$("#form").submit(function(event) {
if(!$("#change").hasClass("has-error") && !$("#name1").hasClass("has-error")
&& !$("#contact1").hasClass("has-error") && !$("#batch1").hasClass("has-error")){
alert("submitting");
event.preventDefault();
var $form=$(this);
name1=$("#name").val();
contact1=$("#contact").val();
email1=$("#email").val();
city1=$form.find("input[name='city']").val();
company1=$form.find("input[name='company']").val();
url=$form.attr("action");
var posting= $.post("some_link.php",{ name:name1,contact:contact1,email:email1,city:city1,company:company1});
posting.done(function(data){
alert("form submitted successfully");
)
})
$("#reset").click();
return false;
}
else return false;
});
but this is posting form by GET
method not by POST
method and also url form is redirected to other php page instead for remaining on this page. 但这是通过GET
方法而不是POST
方法发布的表单,并且url表单也被重定向到其他php页面,而不是保留在该页面上。
here is how link look like http://www.example.com/current_page.php?name=jhgjk&contact=lksjf&email=lkdj%40ldkjf.clj&city=&company=
but i want a normal post method as usually done by including method="post"
in form 这是链接的外观,看起来像http://www.example.com/current_page.php?name=jhgjk&contact=lksjf&email=lkdj%40ldkjf.clj&city=&company=
但我想要一个普通的发布方法,通常通过包括method="post"
形式
EDIT i got the mistake i was doing. 编辑我弄错了我在做。 i was missing a closing bracket for $.post and this was the reason the code was not working and i was banging my head. 我错过了$ .post的右括号,这就是代码无法正常工作的原因,而且我还在努力。
I think you'd be much better using a technology called $.ajax : 我认为使用$ .ajax技术会更好:
$("#form").submit(function(e) {
if(!$("#change").hasClass("has-error") && !$("#name1").hasClass("has-error")
&& !$("#contact1").hasClass("has-error") && !$("#batch1").hasClass("has-error")){
e.preventDefault();
alert("submitting");
$.ajax({
url: 'some-link.php',
type: 'POST',
data: $(this).serialize(),
success: function(data) {
alert('success!');
},
error: function(data) {
alert('error');
}
});
}
else return false;
});
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.