将选定的数据从表插入到另一个表

Question

I want to add the selected data from table1 to another table2 here's my supposed output.

Product Inventory List <-- displays the added product from 2nd table

Product List <-- this one display the products from 1st table

In "Product List" I have my one listed product then if I click the "Add" Link, the data should be listed in the "Product Inventory List"

Anyway here's my code for displaying the data of 1st table

<?php 
$product_list = "";
$sql = mysql_query("SELECT * FROM productinformation1 ORDER BY date_added DESC");
$productCount=mysql_num_rows($sql);
if($productCount>0){
    while($row = mysql_fetch_array($sql)){
        $id = $row["ProductNo"];
        $product_name = $row["ProdName"];
        $product_list .= "Product ID:&nbsp;$id - $product_name &nbsp; &nbsp;&nbsp; &nbsp; &bull; <a href='#'>Edit</a><br>";
    }
}else{
    $product_list = "You have no products listed in your store yet.";
}

?>

And here's my code for displaying the data of 2nd table

<?php
$productsDB = "";
$sql1 = mysql_query("SELECT * FROM productinformation");
$productDBcount=mysql_num_rows($sql1);
if($productDBcount>0){
        while($row = mysql_fetch_array($sql1)){
        $id1 = $row["ProductNo"];
        $product_name = $row["ProdName"];
        $productsDB .= "Product ID:&nbsp;$id1 - $product_name &nbsp; &nbsp; &bull; <a href='product-add.php'> Add </a><br>";
        }
    }else{
    $productsDB = "You have no products listed in your store yet.";
}

?>

As you can see in displaying the data of 2nd table there's a link which is the "Add" and now I want that link function as well..

And I don't know how get the data of 1st table and insert it in 2nd table so that it will this display in my "Product Inventory List"

Please help me.

Answer 1

your link should look like:

<a href='product-add.php?idtoadd=".$id1."'> Add </a>

and in product-add.php you will be able to do:

$sql = "insert ignore into productinformation1 (ProductNo, ProdName)
select ProductNo, ProdName from productinformation
where ProductNo = " . intval($_GET['idtoadd'], 10);

NOTE1: do not use mysql_### functions, use PDO or mysqli

NOTE2: do not use single quotes in HTML attributes, use double quotes