评估ng-controller中的表达式
[英]Evaluating expression in ng-controller
问题描述
My Javascript 
我的Javascript
var app = angular.module('Demo', []);
app.controller('DemoCtrl', function ($scope) {
$scope.expr = "Test"
});
app.controller('Test', function ($scope) {
$scope.HELLO = "HEllo World";
});
My Mark Up 我的马克
<body ng-controller="DemoCtrl">
<div ng-controller="{{expr}}">{{HELLO}}</div>
</body>
This does not work.The documentation says that ng-controller can evaluate expressions.What am I doing wrong ? 这不起作用。文档说ng-controller可以评估表达式。我做错了什么？
JSBIn Link ( http://jsbin.com/ubevel/13/edit ) JSBIn Link （ http://jsbin.com/ubevel/13/edit ）
2 个解决方案
解决方案1
6 2013-10-26 09:54:02
Write controller as function (not as app.controller('Test' ) 将控制器写为函数（而不是app.controller('Test' ）
Change JS to: 将JS更改为：
var app = angular.module('Demo', []);
app.controller('DemoCtrl', function ($scope) {
$scope.expr = Test;
});
function Test($scope) {
$scope.HELLO = "HEllo World";
}
And HTML: 和HTML：
<body ng-controller="DemoCtrl">
<div ng-controller="expr">{{HELLO}}</div>
</body>
解决方案2
3 已采纳 2013-10-26 15:20:19
That is the expected behaviour and a clearer reading of the docs further clarifies it: 这是预期的行为，更清楚地阅读文档进一步澄清了它：
Name of a globally accessible constructor function or an expression that on the current scope evaluates to a constructor function.
Hence, one can either use a string, or one can use an expression which returns a constructor for the controller, but not an expression which returns a string which is the name of the controller. 因此，可以使用字符串，也可以使用返回控制器构造函数的表达式，但不能返回返回字符串的表达式，该字符串是控制器的名称。
As to how to make it work, Maxim has already largely answered your question: by making the expression return a constructor for the controller. 至于如何使它工作，Maxim已经在很大程度上回答了你的问题：通过使expression返回控制器的构造函数。
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