[英]Make one javascript toggle button turn off another
I have some javascript toggle buttons; 我有一些JavaScript切换按钮; that toggle some content;
切换一些内容; and they are next to each other and work independently;
他们彼此相邻,独立工作; the only problem is that I want it so that when you toggle one "div" on;
唯一的问题是我想要它,以便当您打开一个“ div”时; the other one will disappear and vice versa.
另一个将消失,反之亦然。 Right now if you toggle one and then toggle the other they both show at the same time.
现在,如果您先切换一个然后再切换另一个,则它们都将同时显示。 I have tried to change this code myself and cannot figure it out, so I was wondering if anyone knows how to adapt this.
我试图自己更改此代码,但无法弄清楚,所以我想知道是否有人知道如何适应此代码。 the page is here: ( http://gtdsites.com/1a-toggle-buttons/ ).
该页面位于此处:( http://gtdsites.com/1a-toggle-buttons/ )。
Here is my code: 这是我的代码:
<script type="text/javascript">
function toggleMe(btn,a){
var e1=document.getElementById(a);
if(!e1)return true;
if(e1.style.display=="none"){
e1.style.display="block";
btn.value = "MENU";
}
else{
e1.style.display="none";
btn.value = "MENU";
}
return true;
}
</script>
<script type="text/javascript">
function toggleMe1(btn,a2){
var e2=document.getElementById(a2);
if(!e2)return true;
if(e2.style.display=="none"){
e2.style.display="block";
btn.value = "CART";
}
else{
e2.style.display="none";
btn.value = "CART";
}
return true;
}
</script>
<div id="mobile_buttons_cont">
<input class="mobile_buttons" type="button" onclick="return toggleMe(this,'gman123')"
value="MENU" >
<input class="mobile_buttons" type="button" onclick="return toggleMe1(this,'gman124')"
value="CART">
</div>
<div id="gman123" style="display: none">
<br/>
<ul class="gsites_header2">
<li class="gsites_header2">
<a href="/contact/">CONTACT</a>
</li>
<li class="gsites_header2">
<a href="/services/">SERVICES</a>
</li>
<li class="gsites_header2">
<a href="/index/">INDEX</a>
</li>
</ul>
</div>
<div id="gman124" style="display: none">
<br/>
<?php
echo do_shortcode('[do_widget id=cart66cartwidget-2]');
?>
</div>
The quickest and easiest way to do this would be to just set the display of the other one to 'none'
whenever you open one. 最快,最简单的方法是在每次打开一个显示器时将另一个显示器的显示设置为
'none'
。 For example, you could just add this line of code document.getElementById(a2).display='none';
例如,您可以只添加以下代码行
document.getElementById(a2).display='none';
above e1.style.display="block";
高于
e1.style.display="block";
. 。
If you wanted to be more robust, or if you're doing this with a lot of divs, you have a couple of options. 如果您想变得更强大,或者要使用大量的div来执行此操作,则有两种选择。 You could put all your divs in an array and check them for whether they're open (or just set them all to
display='none'
if it doesn't slow you down to much). 您可以将所有div放入数组中,并检查它们是否打开(或者将它们全部设置为
display='none'
如果这样做不会使您的速度变慢)。 You could also create an array with the open one and push
and splice
them as needed. 您也可以使用打开的数组创建一个数组,然后根据需要
push
和splice
它们。 I think ultimately, though, you'd be best served by changing the CSS class of a div based on whether it's showing, and that way you can find the shown element(s) quickly using document.getElementsByClassName
. 不过,我认为最终最好的方法是根据div的CSS类是否显示来最好地为您服务,这样您就可以使用
document.getElementsByClassName
快速找到所显示的元素。
Your functions are nearly identical, you can combine them by making the button value a parameter. 您的功能几乎相同,可以通过将按钮值作为参数来组合它们。 And to toggle the other DIV, pass its ID as another parameter.
并切换另一个DIV,将其ID作为另一个参数传递。
<script>
function toggleMe(btn,btnval,thisdiv,otherdiv){
var e1=document.getElementById(thisdiv);
var e2=document.getElementById(otherdiv);
if(!e1 || !e2) {
return true;
}
if(e1.style.display=="none"){
e1.style.display="block";
e2.style.display="none";
} else {
e1.style.display="none";
e2.style.display="block";
}
btn.value = btnval;
return true;
}
</script>
<div id="mobile_buttons_cont">
<input class="mobile_buttons" type="button" onclick="return toggleMe(this, 'MENU', 'gman123', 'gman124')"
value="MENU" >
<input class="mobile_buttons" type="button" onclick="return toggleMe1(this, 'CART', 'gman124', 'gman123')"
value="CART">
</div>
There's a much simpler way of doing this with jQuery's .show()
and .hide()
. 有与jQuery的这样做的更简单的方法
.show()
和.hide()
I got rid of your functions and replaced them with jQuery I also gave the buttons id's to make selecting them easier. 我摆脱了您的函数,并用jQuery替换了它们,还给了按钮id以简化选择它们。 I've also given you 2 examples of the
.show()
and .hide()
method. 我还为您提供了
.show()
和.show()
.hide()
方法的两个示例。
`$("#btn_1").click(function(){
$("#btn_2").hide();
});
$("#btn_2").click(function(){
$("#btn_1").hide();
});
$("#btn_3").click(function(){
$("#btn_3").hide();
});
$("#btn_4").click(function(){
$("#btn_4").hide();
});`
here's the working demo. 这是工作演示。
http://jsfiddle.net/ryanhagz/rFp7w/ http://jsfiddle.net/ryanhagz/rFp7w/
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