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带总和查询的MYSQL案例语句

[英]MYSQL case statement with sum query

Not sure if this is possible - but I am trying to do the following Have a table with following colums 不知道这是否可能-但我正在尝试执行以下操作

 vote_id (primary_key)
 question_id
 user_id
 vote_count

This basically stores all the votes casted by users for a particular question 这基本上存储了用户对特定问题的所有投票

Now in a single query is it possible for me to get the total vote count and check if a particular user has casted his vote or not. 现在,在一个查询中,我就有可能获得总投票数并检查特定用户是否投票。

Something along these lines - lets say for user_id 10 这些内容-假设user_id 10

SELECT sum(vote),
    (
        CASE 
            WHEN (user_id = 10)
                THEN user_id
            ELSE NULL
            END
        ) user_id
FROM vote_question
GROUP BY course_question_id

This obviously doesn't work. 这显然行不通。

What I'm expecting is if a particular user has voted - his user_id should be returned along with vote count - if he not voted - return null 我期望的是特定用户是否已投票-他的user_id应该与投票计数一起返回-如果他未投票-返回null

Thanks 谢谢

That will be: 那将是:

SELECT 
  SUM(vote),
  COUNT(IF(user_id = 10, 1, NULL)) AS has_user_id_10,
FROM 
  vote_question
GROUP BY 
  course_question_id

-this will result with has_user_id_10 greater than zero if user with id 10 cast his vote, and zero - if not. -如果ID为10的用户投票,则has_user_id_10大于零,否则为零;否则,结果为零。 May be you want strict 1 or 0 , then simply replace that with 可能是您想要严格的10 ,然后将其替换为

COUNT(IF(user_id = 10, 1, NULL))>0 AS has_user_id_10

Please try this - 请尝试这个-

select user_id, vote_count
from
(
select sum(vote) vote_count ,user_id, course_question_id from vote_question group by user_id, course_question_id
)
where vote_count <>0;

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